Time (min) A 0 0.617 10 0.536 20 0.456 30 0.375 40 0.294 50 0.214 60 0.133 εb (L/mol) 79.1 Write what is the differential rate law. Predict how fast the reaction would go if the original concentration were tripled. Explain your logic. Use the integrated rate law to predict the concentration at 75 min. Show your calculation here. Calculate the half-life
Time (min) A 0 0.617 10 0.536 20 0.456 30 0.375 40 0.294 50 0.214 60 0.133 εb (L/mol) 79.1 Write what is the differential rate law. Predict how fast the reaction would go if the original concentration were tripled. Explain your logic. Use the integrated rate law to predict the concentration at 75 min. Show your calculation here. Calculate the half-life
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
- Show a sample calculation of how you converted your initial (t = 0) absorbance reading into a concentration.
- Copy and paste your three graphs below. Sample graph titles: “Determination of whether n = [insert order]”.
|
Red |
|
|
Time (min) |
A |
|
0 |
0.617 |
|
10 |
0.536 |
|
20 |
0.456 |
|
30 |
0.375 |
|
40 |
0.294 |
|
50 |
0.214 |
|
60 |
0.133 |
|
|
|
|
εb (L/mol) |
79.1 |
- Write what is the differential rate law.
- Predict how fast the reaction would go if the original concentration were tripled. Explain your logic.
- Use the integrated rate law to predict the concentration at 75 min. Show your calculation here.
- Calculate the half-life of the reactant at 75 min. Show your work here.
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.![em1.png Part 3: Q9 Average absorbance Flask 8 Flask 9 Flask 10 1:1 Ratio so, Flask 11 Part 3: Q Flask 8 Flask 9 Flask 10 Flask 11 Part 3: Q10 Flask 8 Flask 9 Flask 10 Flask 11 Part 3 0.146 0.166 [Fe] -0.002mol/L 0.215 0.294 [FESCN³mol/L) 4.59% 10 5.18*10* 6.64*10* 9.08*10* [FXmol/L) 5.00 *10* 5.00*10* Y=3362x-0.0083 R² = 0.9993 5.00*10* 5.00*10* (Amounts of flask 8 (9 - 11's values are in the spreadsheet) 71% volume 5.00mL Molarity of Fe(NO3))3 = 0.2M Volume of Fe(NO3))3 = 5.00mL Moles of Fe³= Molarity x volume(L) Moles of Fe¹ = 0.2M X 0.005L = 1x10-³mole x [SCN][mol/ 4x10 5×10-4 7x10 1×10 1 Concentration of Fe³ = mole of Fe³ Volume mole of Fe³1x10³ mole G.O05L 8, Average absorbance for solution 8 (same for 9 - 11) Average absorbance for flask 8 = sum of all absorbances / number of readings (0.145 +0.147 +0.148) 3 Using equation of calibration curve's line(slope) of best fit, the average absorbances of the unknown concentrations to determine [FeSCN-Jat equilibrium in solution 8:…](/questions-and-answers/em1.png-...-part-3-q-average-absorbance-flask-and-11-ratio-so-flash-d-flask-10-flask-11-part-3-q-fla/c9657571-599f-4ed4-a5e6-fabcbd26b888){kind=link}
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