Three isomeric compounds with nearly identical boiling points were produced by a CH337 student and injected on the OSU-Cascades Shimadzu gas chromatograph instrument as described in the lecture notes. The resulting chromatogram is shown below. If eachcompound has nearly identical boiling points, determine the relative polarity of each peak by filling in the blanks with the Roman numerals I, II, or III only.Compoundis most polar.Compoundis least polar.Intensity3000-III2000-III1000-2.02.12.22.32.42.52.62.72.82.93.0min

Three compounds are obtained by the chromatogram having peaks of different intensities. All three of…

Three isomeric compounds with nearly identical boiling points were produced by a CH337 student and injected on the OSU-Cascades Shimadzu gas chromatograph instrument as described in the lecture notes. The resulting chromatogram is shown below. I compound has nearly identical boiling points, determine the relative polarity of each peak by filling in the blanks with the Roman numerals I, II, or III only. Compound is most polar. Compound is least polar. Intensity 3000- I II 2000- III 1000- 0-

Three isomeric compounds with nearly identical boiling points were produced by a CH337 student and injected on the OSU-Cascades Shimadzu gas chromatograph instrument as described in the lecture notes. The resulting chromatogram is shown below. I compound has nearly identical boiling points, determine the relative polarity of each peak by filling in the blanks with the Roman numerals I, II, or III only. Compound is most polar. Compound is least polar. Intensity 3000- I II 2000- III 1000- 0-

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

5. Properties and IMF: Chlorophyll a and Chlorophyll b are almost identical in structure, but they separated during TLC. Report the RFs you recorded for both molecules. What functional group(s) are different between them? Then explain these RF values by comparing the IMF present in each molecule to those present in the mobile or stationary phase and how this shaped their affinities for each phase. Use the terms RF, IMF, polar, nonpolar, affinity, mobile phase and stationary phase.
2) Explain why it is common practice to determine a melting point on an unknown compound rapidly first, and then to rerun the melting point slowly.
What is the best Chromatography instrument for analysis of Soluble Protein molecules CG-FID GC-MS LC-MS IC-MS O IC-EC
Complete the following table. In the second column, assign each set of molecules as constitutional isomers, conformational isomers, enantiomers, diastereomers, or identical. For the third column, based on that analysis, indicate for each set of molecules if they are separable or inseparable by SiO2 chromatography.
The following sentence has the format “Statement 1 BECAUSE Statement 2”. Decide whether statement 1 is true, whether statement 2 is true, and whether the REASONING (the ‘BECAUSE’ relationship) between them is valid. Statement 1: “Pentanal has a higher Rf than 1-pentanol in a TLC analysis on a silica gel plate” BECAUSE Statement 2: “both aldehyde and alcohol molecules are attracted to silica by their permanent dipole moments, but only alcohol molecules can donate protons to form hydrogen bonds to silica”. Question 10 options: A Statement 1 and statement 2 are both correct, and the reasoning is valid B Statement 1 and statement 2 are both correct, but the reasoning is NOT valid C Statement 1 is correct, but statement 2 is NOT correct D Statement 1 is NOT correct, but statement 2 is correct E Statement 1 and statement 2 are both NOT correct
Which compound corresponds to Rf = 0.55? Choose one: Need to run reference standards to compare. 1 2 3