Three different brands of automobile batteries, each one having a 42-month warranty, were included in a study of battery lifetime. A random sampl of batteries of each brand was selected and lifetime (in months) was determined, resulting in the following data. Brand 1 Brand 2 45 39 52 47 4 45 41 43 39 44 50 53 48 47 40 Brand 3 50 45 43 48 58 44 48 оно : (1=M2= из State and test the appropriate hypotheses using a significance level of 0.05. State the appropriate null and alternative hypotheses. (Let M₁, M₂, and μ3 be the true mean lifetimes for the three brands.) O Ho: at least two of the three μ's are different На: М1 =H2= из О но : 1 = H2 = из Ha at least two of the three μ's are different H : all three of the u.'s are different
Three different brands of automobile batteries, each one having a 42-month warranty, were included in a study of battery lifetime. A random sampl of batteries of each brand was selected and lifetime (in months) was determined, resulting in the following data. Brand 1 Brand 2 45 39 52 47 4 45 41 43 39 44 50 53 48 47 40 Brand 3 50 45 43 48 58 44 48 оно : (1=M2= из State and test the appropriate hypotheses using a significance level of 0.05. State the appropriate null and alternative hypotheses. (Let M₁, M₂, and μ3 be the true mean lifetimes for the three brands.) O Ho: at least two of the three μ's are different На: М1 =H2= из О но : 1 = H2 = из Ha at least two of the three μ's are different H : all three of the u.'s are different
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section: Chapter Questions
Problem 8SGR
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Question
![Three different brands of automobile batteries, each one having a 42-month warranty, were included in a study of battery lifetime. A random sample
of batteries of each brand was selected and lifetime (in months) was determined, resulting in the following data.
Ha
Brand 1 45 39 52 47 45 41 43
Brand 2
State and test the appropriate hypotheses using a significance level of 0.05.
State the appropriate null and alternative hypotheses. (Let µ₁, µ², and µ3 be the true mean lifetimes for the three brands.)
O Ho : at least two of the three μ's are different
На: М1 =М2 = из
о но : H1 = M2 = из
о но : 1 = H2=Из
H₂ : at least two of the three μ's are different
Brand 3 50 45 43
39 44 50 53 48 47 40
Treatments
Error
Total
: all three of the μ's are different
оно : M1 #M2+ из
H₂ : at least two of the three μ's are the same
O Ho: all three of the μ's are different
H₂ = μ₁ = μ₁₂ = μ3
48 58 44 48
Summarize your calculations in an ANOVA table. (Round your answers to two decimal places.)
Source of
Variation
Sum of
Squares
df
Mean
Square
F
Use technology to find the P-value. (Round your answer to four decimal places.)
P-value =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c1a7cdd-e96b-43f1-9c5c-bed1a4b6a5fd%2Fdcd46607-ca1a-4d0d-b7fc-90e85116c4c1%2Fne3ta1f_processed.png&w=3840&q=75)
Transcribed Image Text:Three different brands of automobile batteries, each one having a 42-month warranty, were included in a study of battery lifetime. A random sample
of batteries of each brand was selected and lifetime (in months) was determined, resulting in the following data.
Ha
Brand 1 45 39 52 47 45 41 43
Brand 2
State and test the appropriate hypotheses using a significance level of 0.05.
State the appropriate null and alternative hypotheses. (Let µ₁, µ², and µ3 be the true mean lifetimes for the three brands.)
O Ho : at least two of the three μ's are different
На: М1 =М2 = из
о но : H1 = M2 = из
о но : 1 = H2=Из
H₂ : at least two of the three μ's are different
Brand 3 50 45 43
39 44 50 53 48 47 40
Treatments
Error
Total
: all three of the μ's are different
оно : M1 #M2+ из
H₂ : at least two of the three μ's are the same
O Ho: all three of the μ's are different
H₂ = μ₁ = μ₁₂ = μ3
48 58 44 48
Summarize your calculations in an ANOVA table. (Round your answers to two decimal places.)
Source of
Variation
Sum of
Squares
df
Mean
Square
F
Use technology to find the P-value. (Round your answer to four decimal places.)
P-value =
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