three children. What is the probability that one their children will be normal (unaffected) and two children will have the recessive mutant phenotype? Show your work. Please answer this question using the Bayes’ Theorem
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A couple who are both heterozygous for an autosomal recessive mutation that is narrowly expressed and fully penetrant are planning on having three children. What is the probability that one their children will be normal (unaffected) and two children will have the recessive mutant
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- Pompe disease is a glycogen storage disorder caused by a lack of a-glucosidase, the enzyme that converts glycogen to glucose in the muscles. Babies born with this disorder die by the age of two. Pompe disease is a genetic disorder caused by the presence of two recessive autosomal alleles. A man and a woman heterozygous for the condition have two female unaffected children. Determine the probability, expressed as a whole number percentage, of a third baby being born a male with Pompe disease. Your answer must include the use of a Punnett square as well as a legend indicating the allele symbols used.You are discussing the genetic pedigree of a client with a history of autosomal dominant disease in his family. You explain that while a recessive mutation requires both copies of the gene to be mutated in order to cause clinical disease, an autosomal dominant mutation can cause disease when only one copy of the gene is affected. Describe the different mechanisms by which dominance occurs, giving examples of each.Pompe disease is a glycogen storage disorder caused by a lack of ⍺-glucosidase, the enzyme that converts glycogen to glucose in the muscles. Babies born with this disorder die by the age of two. Pompe disease is a genetic disorder caused by the presence of two recessive autosomal alleles. A man and a woman heterozygous for the condition have two female unaffected children. Determine the probability, expressed as a whole number percentage, of a third baby being born a male with Pompe disease. Your answer must include the use of a Punnett square as well as a legend indicating the allele symbols used. (2 marks)
- Cystic fibrosis in humans is caused by mutations in a single gene and is inherited as an autosomal (non-sex chromosome) recessive trait. An unaffected couple has two children. The first child has cystic fibrosis, and the second child is unaffected. What is the probability that the second child is a carrier (heterozygous) for the mutation that causes the disease? 2/3 1 1/2 3/4Albinism, lack of pigmentation in humans, results from an autosomal recessive gene designated a. Two parents with normal pigmentation have an albino child. What is the probability that their next child will be albino? What is the probability that the next child will be an albino girl? If the child is normal, what is the probability that it will be a carrier (heterozygous) for the albino gene?A male dog is a carrier for the autosomal recessive disorders centronuclear myopathy (Y/y) and von Willebrand disease (D/d). The male dog mates with a female dog that is homozygous recessive for both traits (this female dog has both disorders). How many puppies in an 8-puppy litter would you expect to have centronuclear myopathy and NOT have von Willebrand disease? 1 2 3 4
- Albinism and sickle cell anemia are both autosomal recessive disorders that are expressed only in the homozygous state. Two parents who are carriers for both albinism and sickle cell anemia plan to have a child. What is the probability that the child will have exactly one of the conditions? 3/8 7/16 O 1/16 O 1/4 9/16Regarding Mendelian inheritance in diploid individuals, (Read each statement carefully. Select all of the statements below that are true (that you agree with). Leave any statements that are false (that you do not agree with) un- selected.) a diploid individual receives two copies of every autosome from the previous generation. for every autosomal gene inherited by an individual, both copies can come from one parent. a diploid individual gives two copies of every autosome to a child in the next generation. to be diploid means that two independent genes are specified in the individual's genotype.Tuberous Sclerosis (TS) is an autosomal dominant genetic disease characterized by seizures, mental retardation, autism, and benign tumors of the brain, heart, skin, and kidneys. The kidney tumors can also be malignant. This disease exhibits a wide range of severity, and only about 1/3 of the cases are inherited. Two different genes have been tightly linked to the disease in families where it is inherited. The remaining 2/3 appear to be due to mutations in one of the 2 genes as well. Overall it appears that 1/2 are caused by mutations in TSC1 and the other half by mutations in TSC2. A rat model for hereditary renal carcinoma (kidney cancer) has been found. Southern and Northern blot analysis of the TSC1 and TSC2 gene revealed no differences between these rats and normal rats. Not all the rats in the strain would get cancer but a significant proportion did and those were selected for and used in experiments. 1. a) What was detected by the Southern blots? (look this up, make your…
- Consider an autosomal recessive disease in which an individual must inherit two recessive alleles to display the disease phenotype. What is the probability that a woman who is a heterozygous for the trait and a man who is homozygous for the dominant allele will produce an offspring with the autosomal recessive phenotype? Assume no new mutations occur. Select one 1.) 100% 2.)25% 3.) 0% 4.)50% 5.) More information is neededCongenital hypertrichosis (CH) is a very rare X-linked dominant inherited condition. CH is characterized by the growth of dark hair over the body. CH is so rare, only 50 cases have been identified since the Middle Ages. The incidence of this condition is considerably higher in a small Mexican village (from which the partial pedigree below is derived) than the rest of the human population. I II III Use the following information to answer the two questions. IV D II-4 8 9 IV-6 0=10~ 11 1. Using appropriate nomenclature, identify the genotypes for the following 2 individuals: 12 13 your response must include an appropriate legend/key to identify allele symbols. 2. Show how a Punnett square (using the allele symbols from the previous question) is used to determine the probability in percent of individuals III-11 and III-12 next offspring has CH?A woman diagnosed with early-onset Alzheimer's due to a mutation of the APP genehas children with a man that has no family history of familial Alzheimer's. Give the probability of each possible genotype with corresponding phenotype. (The woman has two possible allele combinations. You must show both possibilities)
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