This solution contains two solutes: sulfuric acid (H2SO4) and potassium iodate (KIO3). Since pure H2SO4 is not safe to handle, 0.080 M H2SO4 (a dilute solution of sulfuric acid) is prepared ahead of time for your use. The second solute, potassium iodate (KIO3) is a solid. To obtain solution (2), you will weigh the desired amount of KIO3 and add it to the 0.080 M H2SO4 solution. 6. Calculate the mass of KIO3 needed to prepare 50.0 mL of 0.200 M KIO3. Your answer should have the correct number of sig figs.
This solution contains two solutes: sulfuric acid (H2SO4) and potassium iodate (KIO3). Since pure H2SO4 is not safe to handle, 0.080 M H2SO4 (a dilute solution of sulfuric acid) is prepared ahead of time for your use. The second solute, potassium iodate (KIO3) is a solid. To obtain solution (2), you will weigh the desired amount of KIO3 and add it to the 0.080 M H2SO4 solution. 6. Calculate the mass of KIO3 needed to prepare 50.0 mL of 0.200 M KIO3. Your answer should have the correct number of sig figs.
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter15: Solutions
Section: Chapter Questions
Problem 121AP: Calcium carbonate, CaCO3, can be obtained in a very pure state. Standard solutions of calcium ion...
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