This solution contains two solutes: sulfuric acid (H2SO4) and potassium iodate (KIO3). Since pure H2SO4 is not safe to handle, 0.080 M H2SO4 (a dilute solution of sulfuric acid) is prepared ahead of time for your use. The second solute, potassium iodate (KIO3) is a solid. To obtain solution (2), you will weigh the desired amount of KIO3 and add it to the 0.080 M H2SO4 solution. 6. Calculate the mass of KIO3 needed to prepare 50.0 mL of 0.200 M KIO3. Your answer should have the correct number of sig figs.

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This solution contains two solutes: sulfuric acid (H2SO4) and potassium iodate
(KIO3). Since pure H2SO4 is not safe to handle, 0.080 M H2SO4 (a dilute
solution of sulfuric acid) is prepared ahead of time for your use. The second
solute, potassium iodate (KIO3) is a solid. To obtain solution (2), you will
weigh the desired amount of KIO3 and add it to the 0.080 M H2SO4 solution.
6. Calculate the mass of KIO3 needed to prepare 50.0 mL of 0.200 M KIO3.
Your answer should have the correct number of sig figs.
Transcribed Image Text:This solution contains two solutes: sulfuric acid (H2SO4) and potassium iodate (KIO3). Since pure H2SO4 is not safe to handle, 0.080 M H2SO4 (a dilute solution of sulfuric acid) is prepared ahead of time for your use. The second solute, potassium iodate (KIO3) is a solid. To obtain solution (2), you will weigh the desired amount of KIO3 and add it to the 0.080 M H2SO4 solution. 6. Calculate the mass of KIO3 needed to prepare 50.0 mL of 0.200 M KIO3. Your answer should have the correct number of sig figs.
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