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This question uses the same experimental setup as in Question 1 and the same modification of the attached figure (Figure 2.5 of your textbook). The modification is that the KCL solutions in the middle panel are replaced with NaCl solutions (1 mM on the left or inside and 10 mM on the right or outside). What would initially happen if the membrane was made permeable to Na+? (A) Lure D A Inside 1 mM KQ Voltmotor V=0 elle Outside 1 mM KCI Termeable to K* No net flux of K* K' lon (B) Initial conditions ● lo 6 Inside 10 πιΜ KCl Initially V=0 очен Outside 1 mM KCI Net flux of K from inside to outside At equilibrium V in-out= -38 my a ✪ m O Inside Outside 10 mM KC 1 mM ka Flux of K* from inside to outside balanced by opposing membning potential Membrane potential V₁ (mv) 8 -116 100 -2 [K' (MM) 10 108 Na+ would move up its concentration gradient from the left (inside) to the right (outside) compartment. Na+ would move down its concentration gradient from the right (outside) to the left (inside) compartment. Na+ would not move because it is at equilibrium. Slope 58 mV per tenfold change in K gradient Na+ would not move because it has a valence (i.e.. charge) of 1+. 0

This question uses the same experimental setup as in Question 1 and the same modification of the attached figure (Figure 2.5 of your textbook). The modification is that the KCL solutions in the middle panel are replaced with NaCl solutions (1 mM on the left or inside and 10 mM on the right or outside). What would initially happen if the membrane was made permeable to Na+? (A) Lure D A Inside 1 mM KQ Voltmotor V=0 elle Outside 1 mM KCI Termeable to K* No net flux of K* K' lon (B) Initial conditions ● lo 6 Inside 10 πιΜ KCl Initially V=0 очен Outside 1 mM KCI Net flux of K from inside to outside At equilibrium V in-out= -38 my a ✪ m O Inside Outside 10 mM KC 1 mM ka Flux of K* from inside to outside balanced by opposing membning potential Membrane potential V₁ (mv) 8 -116 100 -2 [K' (MM) 10 108 Na+ would move up its concentration gradient from the left (inside) to the right (outside) compartment. Na+ would move down its concentration gradient from the right (outside) to the left (inside) compartment. Na+ would not move because it is at equilibrium. Slope 58 mV per tenfold change in K gradient Na+ would not move because it has a valence (i.e.. charge) of 1+. 0

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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This question uses the same experimental setup as in Question 1 and the same modification of the attached figure (Figure 2.5 of your textbook). The modification is that the KCL solutions in the middle panel are replaced with NaCl solutions (1 mM on the left or inside and 10 mM on the right or outside). What would initially happen if the membrane was made permeable to Na+? (A) Lure D A Inside 1 mM KQ Voltmotor V=0 elle Outside 1 mM KCI Termeable to K* No net flux of K* K' lon (B) Initial conditions ● lo 6 Inside 10 πιΜ KCl Initially V=0 очен Outside 1 mM KCI Net flux of K from inside to outside At equilibrium V in-out= -38 my a ✪ m O Inside Outside 10 mM KC 1 mM ka Flux of K* from inside to outside balanced by opposing membning potential Membrane potential V₁ (mv) 8 -116 100 -2 [K' (MM) 10 108 Na+ would move up its concentration gradient from the left (inside) to the right (outside) compartment. Na+ would move down its concentration gradient from the right (outside) to the left (inside) compartment. Na+ would not move because it is at equilibrium. Slope 58 mV per tenfold change in K gradient Na+ would not move because it has a valence (i.e.. charge) of 1+. 0
Transcribed Image Text:This question uses the same experimental setup as in Question 1 and the same modification of the attached figure (Figure 2.5 of your textbook). The modification is that the KCL solutions in the middle panel are replaced with NaCl solutions (1 mM on the left or inside and 10 mM on the right or outside). What would initially happen if the membrane was made permeable to Na+? (A) Lure D A Inside 1 mM KQ Voltmotor V=0 elle Outside 1 mM KCI Termeable to K* No net flux of K* K' lon (B) Initial conditions ● lo 6 Inside 10 πιΜ KCl Initially V=0 очен Outside 1 mM KCI Net flux of K from inside to outside At equilibrium V in-out= -38 my a ✪ m O Inside Outside 10 mM KC 1 mM ka Flux of K* from inside to outside balanced by opposing membning potential Membrane potential V₁ (mv) 8 -116 100 -2 [K' (MM) 10 108 Na+ would move up its concentration gradient from the left (inside) to the right (outside) compartment. Na+ would move down its concentration gradient from the right (outside) to the left (inside) compartment. Na+ would not move because it is at equilibrium. Slope 58 mV per tenfold change in K gradient Na+ would not move because it has a valence (i.e.. charge) of 1+. 0
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