(This problem requires values in your textbook's specific appendices, which you can access through the OWLv2 MindTap Reader. Ye AS and then calculate pt AS for each of the following reactions. pt pt pt pt Tables to answer this question as the values will not match.) 1 H2(g) + O2(g) → H₂O(1) a. AS is negative. AS°= = -163.65 J/K 2CH, CHO(g) +502(g) 4C02 (9)+4H₂O(g) b. AS is positive. pt pt pt Correct AS= = 82.7 J/K pt pt HCl(g) →H(aq) + Cl(aq) c. AS is positive. pt AS = pt pt Submit Answer J/K Try Another Version 10 item attempts remaining

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.35QE
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(This problem requires values in your textbook's specific appendices, which you can access through the OWLv2 MindTap Reader. Ye
AS and then calculate
pt
AS for each of the following reactions.
pt
pt
pt
pt
Tables to answer this question as the values will not match.)
1
H2(g) + O2(g) → H₂O(1)
a. AS is negative.
AS°= = -163.65 J/K
2CH, CHO(g) +502(g) 4C02 (9)+4H₂O(g)
b. AS is positive.
pt
pt
pt
Correct
AS= = 82.7
J/K
pt
pt
HCl(g) →H(aq) + Cl(aq)
c. AS is positive.
pt
AS =
pt
pt
Submit Answer
J/K
Try Another Version 10 item attempts remaining
Transcribed Image Text:(This problem requires values in your textbook's specific appendices, which you can access through the OWLv2 MindTap Reader. Ye AS and then calculate pt AS for each of the following reactions. pt pt pt pt Tables to answer this question as the values will not match.) 1 H2(g) + O2(g) → H₂O(1) a. AS is negative. AS°= = -163.65 J/K 2CH, CHO(g) +502(g) 4C02 (9)+4H₂O(g) b. AS is positive. pt pt pt Correct AS= = 82.7 J/K pt pt HCl(g) →H(aq) + Cl(aq) c. AS is positive. pt AS = pt pt Submit Answer J/K Try Another Version 10 item attempts remaining
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