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this is ONE question, please answer both short parts. Thank you.

this is ONE question, please answer both short parts. Thank you.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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this is ONE question, please answer both short parts. Thank you. 

What we know intuitively above is that there there is a point on objects that may be balanced by a pivot. So instead of looking at the mass all along the rod above, we can think of all the mass being centered at one point to achieve this balance. We call this quantity the center of mass. We can think of extended object being made up of millions of point masses. These points can then be reduced to a single point where all the mass is concentrated, i.e. the center of mass. In one-dimension, if we have n point masses of mass m;, for the ith mass with position vector x; , then the center of mass for the system of n masses is given as Хсм XCM = where E m; = M (the M sum of all the masses) For example, say we have a heavy rod, m, with two hanging masses, m, and m2. First we need to define a coordinate system (e.g. where the origin is), and then we can use the formula above. Let's say our origin is in the middle of the bar, then the center of mass is XCM = 0-m, thm1+l2m2 m,+m1+m2 where the hanging masses are at a distance I from the center.
Transcribed Image Text:What we know intuitively above is that there there is a point on objects that may be balanced by a pivot. So instead of looking at the mass all along the rod above, we can think of all the mass being centered at one point to achieve this balance. We call this quantity the center of mass. We can think of extended object being made up of millions of point masses. These points can then be reduced to a single point where all the mass is concentrated, i.e. the center of mass. In one-dimension, if we have n point masses of mass m;, for the ith mass with position vector x; , then the center of mass for the system of n masses is given as Хсм XCM = where E m; = M (the M sum of all the masses) For example, say we have a heavy rod, m, with two hanging masses, m, and m2. First we need to define a coordinate system (e.g. where the origin is), and then we can use the formula above. Let's say our origin is in the middle of the bar, then the center of mass is XCM = 0-m, thm1+l2m2 m,+m1+m2 where the hanging masses are at a distance I from the center.
Consider point masses of 100 mg, 200 mg, 5 gm, 500 gm, and 2 kg located along a straight line at 10 cm, 30 cm, 5 cm, -50 cm, and -1 m respectively. The origin is at 0. Find the location of the center of mass of this system of five masses. (Assume all measurements have 3 significant figures of precision) 2 m 0.563 m O - 0.898 m - 0.924 m O - 2 m A -8 A circular disk is shown as above. Which of the following is the location of the center of mass of the disk? O A O E
Transcribed Image Text:Consider point masses of 100 mg, 200 mg, 5 gm, 500 gm, and 2 kg located along a straight line at 10 cm, 30 cm, 5 cm, -50 cm, and -1 m respectively. The origin is at 0. Find the location of the center of mass of this system of five masses. (Assume all measurements have 3 significant figures of precision) 2 m 0.563 m O - 0.898 m - 0.924 m O - 2 m A -8 A circular disk is shown as above. Which of the following is the location of the center of mass of the disk? O A O E
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