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The picture is the complete guide for solution. Pls make it like that. Thankkkkyoouuuuuu   : Solve completely what is given and required by converting the units based on the DENSITY units. EXPRESSED ALL ANSWER TO SCIENTIFIC NOTATION to THREE SIGNIFICANT FIGURES for all the final answer and enclosed with a box each converted units and affix the required units.        SET E: A 450g of toblerone with a triangular trough in shape has the following dimensions of 6 ft in length, the base is 4 in. And stands 3.5 cm. Calculate the density in Kg/L and its specific gravity?    V= 1/2bhl

The picture is the complete guide for solution. Pls make it like that. Thankkkkyoouuuuuu   : Solve completely what is given and required by converting the units based on the DENSITY units. EXPRESSED ALL ANSWER TO SCIENTIFIC NOTATION to THREE SIGNIFICANT FIGURES for all the final answer and enclosed with a box each converted units and affix the required units.        SET E: A 450g of toblerone with a triangular trough in shape has the following dimensions of 6 ft in length, the base is 4 in. And stands 3.5 cm. Calculate the density in Kg/L and its specific gravity?    V= 1/2bhl

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The picture is the complete guide for solution. Pls make it like that. Thankkkkyoouuuuuu

 

: Solve completely what is given and required by converting the units based on the DENSITY units. EXPRESSED ALL ANSWER TO SCIENTIFIC NOTATION to THREE SIGNIFICANT FIGURES for all the final answer and enclosed with a box each converted units and affix the required units. 

 

 

 

SET E: A 450g of toblerone with a triangular trough in shape has the following dimensions of 6 ft in length, the base is 4 in. And stands 3.5 cm. Calculate the density in Kg/L and its specific gravity? 

 

V= 1/2bhl

SET A: A 3.0g of cubic ice has a dimension of 1.5 cm. in each sides. Calculate the density into Ibs./ft, and also its specific gravity? V = S Given: Solution: P=2 M = 3.0 g – Ibs. 1x 100g = 3.0 g x 1 Kg 1x103g 2.2 lbs M = 3.0 g 1 g 1 Kg (3.0) (1x 100) (2.2) = 6.6 x 10° Ibs. V = 1.5° cm 1x 103 = 3.38 cm V = 3.38 cm – ft 1 in.3 16.387 cm3 1 ft3 1728 in.3 = 3.38 cm x (3.38) = 1.19 x 104 ft (16.387) (1728) Final Given: 6.6 x 10-3 lbs. 5.55 x 10' Ibs./ft? P = ? 1.19 x 10-4 ft3 5.55 x 101 lbs./ft3 62.4 lbs./ft3 M = 6.6 x 10 Ibs. Sp. Gr. = = 8.89 x 101 V = 1.19 x 104 ft
Transcribed Image Text:SET A: A 3.0g of cubic ice has a dimension of 1.5 cm. in each sides. Calculate the density into Ibs./ft, and also its specific gravity? V = S Given: Solution: P=2 M = 3.0 g – Ibs. 1x 100g = 3.0 g x 1 Kg 1x103g 2.2 lbs M = 3.0 g 1 g 1 Kg (3.0) (1x 100) (2.2) = 6.6 x 10° Ibs. V = 1.5° cm 1x 103 = 3.38 cm V = 3.38 cm – ft 1 in.3 16.387 cm3 1 ft3 1728 in.3 = 3.38 cm x (3.38) = 1.19 x 104 ft (16.387) (1728) Final Given: 6.6 x 10-3 lbs. 5.55 x 10' Ibs./ft? P = ? 1.19 x 10-4 ft3 5.55 x 101 lbs./ft3 62.4 lbs./ft3 M = 6.6 x 10 Ibs. Sp. Gr. = = 8.89 x 101 V = 1.19 x 104 ft
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