This chart shows the results of two random samples that measured the average number of minutes per charge for AA Lithium-ion (Li-ion) rechargeable batteries versus Nickel-Metal Hydride (NiMH) rechargeable batteries. Down below shows the hypothesis test using significance level (α) = 0.05 to determine if the true average number of minutes per charge for NiMH batteries is smaller than that for Li-ion batteries.     1. From the data given from the first graph below, what would be the correct p value? (the one tail or the two tail?)   t-Test: Two-Sample Assuming Unequal Variances                 NiMH Li-ion   Mean 89.35714 95   Variance 3.93956 59.75   Observations 14 17   Hypothesized Mean Difference 0     df 19     t Stat -2.89621     P(T<=t) one-tail 0.004628     t Critical one-tail 1.729133     P(T<=t) two-tail 0.009255     t Critical two-tail 2.093024     For the bottom graph: 1.. Find the point estimate (you can do this by subtracting Group 2 Sample Mean from Group 1 Sample Mean.) 2. Find the Lower Bound of the confidence interval by subtracting the Margin of Error from the point estimate. 3. Find the Upper Bound by adding the margin of error to the point estimate. Comparing Two Means When Variances Are NOT equal               Group 1 Sample Mean: 89.35714     Group 1 Sample Standard Deviation: 3.93956  = SQRT(Variance)   Group 1 Sample Size: 14     Group 2 Sample Mean: 95     Group 2 Sample Standard Deviation: 59.75  = SQRT(Variance)   Group 2 Sample Size: 17     Alpha: 0.05  =1-Conf level   Hypothesized Mean Difference: 0 This usually is zero           Degrees of Freedom: 16.16881     Standard Error (SE) 14.52970     Test Statistic: -0.38837     P(T<=t) one-tail 0.35143     P(T<=t) two-tail 0.70286     Margin of Error (ME) 30.80159

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This chart shows the results of two random samples that measured the average number of minutes per charge for AA Lithium-ion (Li-ion) rechargeable batteries versus Nickel-Metal Hydride (NiMH) rechargeable batteries. Down below shows the hypothesis test using significance level (α) = 0.05 to determine if the true average number of minutes per charge for NiMH batteries is smaller than that for Li-ion batteries.

 

 

1. From the data given from the first graph below, what would be the correct p value? (the one tail or the two tail?)

 

t-Test: Two-Sample Assuming Unequal Variances      
       
  NiMH Li-ion  
Mean 89.35714 95  
Variance 3.93956 59.75  
Observations 14 17  
Hypothesized Mean Difference 0    
df 19    
t Stat -2.89621    
P(T<=t) one-tail 0.004628    
t Critical one-tail 1.729133    
P(T<=t) two-tail 0.009255    
t Critical two-tail 2.093024  

 

For the bottom graph:

1.. Find the point estimate (you can do this by subtracting Group 2 Sample Mean from Group 1 Sample Mean.)

2. Find the Lower Bound of the confidence interval by subtracting the Margin of Error from the point estimate.

3. Find the Upper Bound by adding the margin of error to the point estimate.

Comparing Two Means When Variances Are NOT equal      
       
Group 1 Sample Mean: 89.35714    
Group 1 Sample Standard Deviation: 3.93956  = SQRT(Variance)  
Group 1 Sample Size: 14    
Group 2 Sample Mean: 95    
Group 2 Sample Standard Deviation: 59.75  = SQRT(Variance)  
Group 2 Sample Size: 17    
Alpha: 0.05  =1-Conf level  
Hypothesized Mean Difference: 0 This usually is zero  
       
Degrees of Freedom: 16.16881    
Standard Error (SE) 14.52970    
Test Statistic: -0.38837    
P(T<=t) one-tail 0.35143    
P(T<=t) two-tail 0.70286    
Margin of Error (ME) 30.80159    

 

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