These are both the same question but just wanted you to see the answer options along with the confidence interval

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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These are both the same question but just wanted you to see the answer options along with the confidence interval
A survey of 50 young professionals found that they spent an average of $23.26 when dining out, with a standard deviation of $12.15. Can you conclude statistically
ITY that the population mean is greater than $26? Use a 95% confidence interval.
The 95% confidence interval is As $26 is
V of the confidence interval, we
conclude that the population mean is greater
than $26.
(Use ascending order. Round to four decimal places
above the upper limit
below the lower limit
within the limits
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Transcribed Image Text:A survey of 50 young professionals found that they spent an average of $23.26 when dining out, with a standard deviation of $12.15. Can you conclude statistically ITY that the population mean is greater than $26? Use a 95% confidence interval. The 95% confidence interval is As $26 is V of the confidence interval, we conclude that the population mean is greater than $26. (Use ascending order. Round to four decimal places above the upper limit below the lower limit within the limits Clear All Check Ansrer Get More Help - View an Example Help Me Solve This ols OK e to search acer
A survey of 50 young professionals found that they spent an average of $23.26 when dining out, with a standard deviation of $12.15. Can you conclude statistically
ITY
that the population mean is greater than $26? Use a 95% confidence interval.
The 95% confidence interval is || ||| As $26 is
V of the confidence interval, we
V conclude that the population mean is greater
than $26.
(Use ascending order. Round to four decimal places as needed.)
cannot
can
Help Me Solve This
View an Example
Get More Help -
Clear All
Is
OK
to search
[]
acer
Transcribed Image Text:A survey of 50 young professionals found that they spent an average of $23.26 when dining out, with a standard deviation of $12.15. Can you conclude statistically ITY that the population mean is greater than $26? Use a 95% confidence interval. The 95% confidence interval is || ||| As $26 is V of the confidence interval, we V conclude that the population mean is greater than $26. (Use ascending order. Round to four decimal places as needed.) cannot can Help Me Solve This View an Example Get More Help - Clear All Is OK to search [] acer
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