Data Table Observation (millimeters) Sample 1 2 3 4 5 6 7 8 1 9.500 8.200 7.600 9.600 7.900 8.000 7.100 9.000 23 2 9.700 8.800 9.800 9.900 9.100 9.900 8.700 9.500 3 7.600 9.000 8.000 7.800 7.600 9.700 7.500 9.800 4 10.100 9.600 7.400 8.400 9.100 8.900 8.000 8.900 5 8.900 7.000 8.500 7.100 9.400 7.900 8.600 8.200
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can someone help me with this? I am getting wrong response. I think it has to due with the deviation or it may be how i configured the USL and LSL. There is only one chart provided for the question.
What is the Cpk. Please round by three decimal places.
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- Area Page 1 Page 2 Area Standard Normal Distribution 0.00 0.01 0,02 0,03 0.04 0.05 0.06 0.07 0.08 0.09 Standard Normal Distribution 0.5319 0.5714 0.6103 0.02 0,08 0.5000 0.5398 0.5793 0.5080 0.5478 0.5871 0.6255 0.6628 0,00 0.03 0.05 0,07 0,5040 0.5438 0.5832 0.6217 0.6591 0.5120 0.5517 0,5910 0.6293 0.6664 0.5199 0.5596 0.5987 0.6368 0.6736 0.5239 0.5636 0.6026 0.6406 0.6772 0.01 0,04 0.06 0,09 0.0 0.0003 0.0005 0.0007 0.0009 0.0013 0.0003 0.0005 0.0006 0.0009 0.0013 0.0003 0.0004 0.0006 0.0008 0.0011 0.0003 0.0004 0.0005 0.0008 0.0011 0.0003 0.0004 0.0005 0.0007 0.0010 0.0002 0.0003 0.0005 0.0007 0.0010 0.1 0.2 0.3 0.4 0.5160 0.5557 0.5948 0.6331 0.6700 0.5279 0.5675 0.6064 0.6443 0.6808 0,5359 0.5753 0.6141 0.6517 0.6879 -3.4 -33 0.0003 0.0005 0.0007 0.0010 0.0013 0.0003 0.0004 0.0006 0.0009 0.0012 0.0003 0.0004 0.0006 0.0008 0.0012 0.0003 0.0004 0.0006 0.0008 0.0011 0.6179 0.6554 0.6480 0.6844 -3.2 -3.1 -3.0 0.6915 0.7257 0.7580 0.7881 0.8159 0,6950 0,7291 0.7611 0.7910 0.8186…Thickness measurements of a coating process are made to the nearest hundredth of a millimeter. The thickness measurements are uniformly distributed with values 0.14, 0.15, 0.16, 0.17, 0.18. Determine the mean and variance of the coating thickness for this process. Round your answers to four decimal places (e.g. 98.7654). (a) mean (in millimeters) (b) variance (in millimeters?) (a) i (b) iDetermine the area under the standard normal curve that lies between (a) Z=-1.55 and Z=1.55, (b) Z=-1.14 and Z=0, and (c) Z=0.13 and Z=2.22. Click the icon to view a table of areas under the normal curve. olve this P (a) The area that lies between Z=-1.55 and Z=1.55 is (Round to four decimal places as needed.) View an example 4x IA Get more help - F4 LDC 0 Tables of Areas under the Normal Curve Area F7 PrtScnfa F8 TABLE V 2 .00 .08 -3.4 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0002 -3.3 0.0005 0.0005 0.0005 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0003 -3.2 0.0007 0.0007 0.0006 0.0006 0.0006 0.0006 0.0006 0.0005 0.0005 0.0005 -3.1 0.0010 0.0009 0.0009 0.0009 0.0008 0.0008 0.0008 0.0008 0.0007 0.0007 -3.0 0.0013 0.0013 0.0013 0.0012 0.0012 0.0011 00011 00011 0.0010 0.0010 -2.9 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014 -2.8 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019 -2.7 0.0035 0.0034 0.0033 0.0032 0.0031…
- Thickness measurements of a coating process are made to the nearest hundredth of a millimeter. The thickness measurements are uniformly distributed with values 278, 278.4843, 278.9686, ..., 296.4034. Determine the variance of the coating thickness for this process. Select one: a. 28.22376096 O b. 29.70922207 O c. 31.29099430 O d. 287.20170000 O e. 28.20421542Find the area to the left of z = -1.5 Solution: Draw the normal curve and shade the required region 2 3 Find the area that z = -1.5 corresponds to an area corresponds to the z-value Examine the graph and use probability notation to form the equation . The proportion of the area to the left of z = -1.5 isDetermine the area under the standard normal curve that lies between (a) Z= -2.23 and Z=2.23. (b) Z=-2.04 and Z=0, and (c) Z= - 2.16 and Z=0.78.
- E Untitled document - Google Doc X 1 VitalSource Bookshelf: Modern BX pook Exercise Not syr 516679/cfi/164!/4/4@0.00:46.6 Exercises Methods 23. Consider a sample with data values of 10, 20, 12, 17, and 16. Compute the range and interquartile range. 24. Consider a sample with data values of 10, 20, 12, 17, and 16. Compute the variance and standard deviation. 25. Consider a sample with data values of 27, 25, 20, 15, 30, 34, 28, and 25. Compute the range, interquartile range, variance, and standard deviation. est Applications 26. Data collected by the Oil Price Information Service from more than 90,000 gasoline and con- venience stores throughout the U.S. showed that the average price for a gallon of unleaded gasoline was $3.28 (MSN Auto website, February 2, 2014). The following data show the price per gallon ($) for a sample of 20 gasoline and convenience stores located in San Francisco. st 3.59 3.57 3.59 3.59 4.79 3.55 3.56 3.99 3.60 3.73 3.75 3.61 3.55 3.71 3.66 3.65 3.63 3.56 3.57…Part 1 of 2 Español (a) The standard normal curve is graphed below. Shade the region under the standard normal curve to the left of z=2.00. 0.3- 0.2- 0.1+ Part 2 of 2 (b) Use this table or the ALEKS calculator to find the area under the standard normal curve to the left of z= 2.00. Give your answer to four decimal places (for example, 0.1234). Save For Later Submit Assignment Check 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use I Privacy Center | Accessibility DII DO 80 a F6 F7 19 esc F3 F4 F2 & %23 6 7 8. delete 1 2 3 4 T Y U Q tab F G H K yRMDMail The Farley Manufacturing Company prides itself on the quality of its products. The company is engaged in competition for a very important project. A key element is a Assi part that ultimately goes into precision testing equipment. The specifications are 8.000 3.000 millimeters. Management is concerned about the capability of the process to produce that part. The accompanying data were randomly collected during test runs of the process. Click the icon to view the data. Do Take The process capability index, C is equal to (Enter your response rounded to three decimal places) Assume that the process is in statistical control. Is the process capable of producing the part at the three-sigma level? Explain. Since C, equals, the process decimal places) (Enter your response rounded to three
- Question Five The management of a supermarket wants to adopt a new promotional policy of giving free gift to every customer who spends more than a certain amount per visit at this supermarket. The expectation of the management is that after this promotional policy is advertised, the expenditure for all customers at this supermarket will be normally distributed with mean 400 £ and a variance of 900 £?. 1) If the management wants to give free gifts to at most 10% of the customers, what should the amount be above which a customer would receive a free gift? 2) In a sample of 100 customers, what are the number of customers whose expenditure is between 420 £ and 485 £? 3) What is a probability of selecting a customer whose expenditure is differ than the population mean expenditure by at most 50 £? 4) In a sample of 49 customers, what are the number of customers whose mean expenditure is at least 410 £? 5) What is the probability that the expenditure of the first customer exceeds the…The per capita energy consumption level (in kilowatt-hours) in a certain country for a recent year can be approximated by a normal distribution, as shown in the figure. (a) What consumption level represents the 9th percentile? (b) What consumption level represents the 19th percentile? (c) What consumption level represents the third quartile? 22504250250Kilowatt-hours μ=2250 kWh σ=579.5 kWh x A normal curve labeled mu = 2250 k W h and sigma = 579.5 k W h is over a horizontal x-axis labeled Kilowatt-hours from 250 to 4250 in increments of 1000 and is centered on 2250. Question content area bottom Part 1 (a) The consumption level that represents the 9th percentile is 11 kilowatt-hours.Question Five The management of a supermarket wants to adopt a new promotional policy of giving free gift to every customer who spends more than a certain amount per visit at this supermarket. The expectation of the management is that after this promotional policy is advertised, the expenditure for all customers at this supermarket will be normally distributed with mean 400 £ and a variance of 900 £?. 1) If the management wants to give free gifts to at most 10% of the customers, what should the amount be above which a customer would receive a free gift? 2) In a sample of 100 customers, what are the number of customers whose expenditure is between 420 £ and 485 £? 3) What is a probability of selecting a customer whose expenditure is differ than the population mean expenditure by at most 50 £? 4) In a sample of 49 customers, what are the number of customers whose mean expenditure is at least 410 £? 5) What is the probability that the expenditure of the first customer exceeds the…