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THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: AH = -80.5 kJ AH = -150 kJ 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AX (g) + ½R2 (g) → XAR (g) Q (s) + R2 (g) → QR2 (s) (Round off final answer to ONE decimal place) AH = -526.4 kJ Round your answer to 1 decimal place.

THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: AH = -80.5 kJ AH = -150 kJ 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AX (g) + ½R2 (g) → XAR (g) Q (s) + R2 (g) → QR2 (s) (Round off final answer to ONE decimal place) AH = -526.4 kJ Round your answer to 1 decimal place.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A,R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: AH = -80.5 kJ 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AH = -150 kJ AH = -526.4 kJ AX (g) + ½R2 (g) - XAR (g) Q (s) + R2 (g) → QR2 (s) (Round off final answer to ONE decimal place) Round your answer to 1 decimal place.
Transcribed Image Text:THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A,R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: AH = -80.5 kJ 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AH = -150 kJ AH = -526.4 kJ AX (g) + ½R2 (g) - XAR (g) Q (s) + R2 (g) → QR2 (s) (Round off final answer to ONE decimal place) Round your answer to 1 decimal place.
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