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The standard enthalpy of combustion of propane, C3H8, is -2.220 x 103 kJ mol-1 at 400 K. Use the data below, and Kirchhoff's law, to calculate the standard enthalpy of combustion at 600 K. The reaction involved is: C3H8 (g) + 5 O2(g) → 3 CO2(g) + 4 H₂O(g) Cp,m (J K-1 mol-1): C3H8 (g) = 73.6; O2(g) = 29.4; H₂O(g) =33.6; CO2(g) =37.1 O 500 kJ mol-1 O-2195 kJ mol-1 O -3395 kJ mol-1 O 2595 kJ mol-1

The standard enthalpy of combustion of propane, C3H8, is -2.220 x 103 kJ mol-1 at 400 K. Use the data below, and Kirchhoff's law, to calculate the standard enthalpy of combustion at 600 K. The reaction involved is: C3H8 (g) + 5 O2(g) → 3 CO2(g) + 4 H₂O(g) Cp,m (J K-1 mol-1): C3H8 (g) = 73.6; O2(g) = 29.4; H₂O(g) =33.6; CO2(g) =37.1 O 500 kJ mol-1 O-2195 kJ mol-1 O -3395 kJ mol-1 O 2595 kJ mol-1

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The standard enthalpy of combustion of propane, C3Hg, is −2.220 x 10³ kJ mol-1 at 400 K. Use the data below, and Kirchhoff's law, to calculate the standard enthalpy of combustion at 600 K. The reaction involved is: C3H8 (g) + 5 O2(g) → 3 CO2(g) + 4 H₂O(g) Cp,m (J K−1 mol¯¹): C3H8 (g) = 73.6; O2(g) = 29.4; H₂O(g) =33.6; CO2(g) =37.1 500 kJ mol-1 O-2195 kJ mol-1 -3395 kJ mol-1 2595 kJ mol-1
Transcribed Image Text:The standard enthalpy of combustion of propane, C3Hg, is −2.220 x 10³ kJ mol-1 at 400 K. Use the data below, and Kirchhoff's law, to calculate the standard enthalpy of combustion at 600 K. The reaction involved is: C3H8 (g) + 5 O2(g) → 3 CO2(g) + 4 H₂O(g) Cp,m (J K−1 mol¯¹): C3H8 (g) = 73.6; O2(g) = 29.4; H₂O(g) =33.6; CO2(g) =37.1 500 kJ mol-1 O-2195 kJ mol-1 -3395 kJ mol-1 2595 kJ mol-1
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