There are many ways to construct a 2-sided 100(1 – a)% confidence interval for µ. In particular, if a = 0.05, explain why - 20.025 < µ <ã+ z0.025' is preferable to I – 20.01 < µ
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Q: You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample…
A: Let. X: The lifespan of a certain species of bacteria in hours. Given: Sample size = n =25 Sample…
Q: You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample…
A: Given,margin of error(E)=0.45standard deviation(S)=5.4α=1-0.95=0.05α2=0.025Z0.025=1.96 (from…
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A: Given that Sample size n =50 Population mean μ =880 Sample mean =871 Standard deviation =21
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Q: You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample…
A: Here, n=40, x-bar=74, s=4.4, E=0.6.
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A: Given, n=450 x-=23.61 σ=50.67
Q: You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample…
A:
Q: You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample…
A:
Q: A researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 25…
A: It is given that the confidence level is 0.99, the standard deviation is 4.4, and the margin of…
Q: A researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 35…
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A: State the hypotheses.
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Q: You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample…
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Q: You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample…
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Q: (a) To answer this, test the following hypotheses at significance level a= 0.05. Ho: µ= 5, Ha: µ>5…
A: xbar= 5.2 s = 1 n =200
Q: You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample…
A: Given,margin of error(E)=0.6standard deviation(s)=5.8α=1-0.98=0.02α2=0.01Z0.01=2.3263 (from…
Q: 1. In the past, a chemical company produced 880 pounds of a certain type of plastic per day. Now,…
A: Given that Sample size n =50 Sample mean =871 Standard deviation =21 Population mean μ =880
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Q: You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample…
A: Given Information : You are a researcher studying the lifespan of a certain species of bacteria. A…
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- A researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 30 bacteria reveals a sample mean of ¯x=68x¯=68 hours with a standard deviation of s=7s=7 hours. He would like to estimate the mean lifespan for this species of bacteria to within a margin of error of 0.75 hours at a 99% level of confidence.What sample size should you gather to achieve a 0.75 hour margin of error?He would need to sample bacteria.You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 30 bacteria reveals a sample mean of ¯x=78x¯=78 hours with a standard deviation of s=4.4s=4.4 hours. You would like to estimate the mean lifespan for this species of bacteria to within a margin of error of 0.6 hours at a 95% level of confidence. What sample size should you gather to achieve a 0.6 hour margin of error? Round your answer up to the nearest whole number. n = bacteriaIn the past, a chemical company produced 880 pounds of a certain type of plastic per day. Now, using a newly developed and less expensive process, the mean daily yield of plastic for the first 50 days of production is 871 pounds; the standard deviation is 21 pounds. Do the data provide sufficient evidence to indicate that the mean daily yield for the new process is less than that of the old procedure? (Use α=0.05) (c) p-value for the test above is
- In the year 2033, Sarai Patterson is a leading traveling nurse. Sarai is interested in reducing the mean recovery time for patients after experiencing a serious injury (assume recovery times are normally distributed). Suppose the mean recovery time is presently 8.6 months. Sarai takes a random sample of 46 patients that have experienced serious injury to participate in a new treatment program and finds the sample mean is 8.1 months and a sample standard deviation of 1.2 months. Using α = 0.05, answer the following questions. a) What is the setup for your null and alternative hypothesis? b) What is the value of the test statistic? c) What is/are the critical value(s)?The average number of heart beats per minute for a random sample of 64 patients was found to be 85 with a standard deviation of 10. Test the hypothesis that the true average number of heart beats is less than 85. Use ά = 0.01. In the past, it was believed that 40% of women felt that men are basically selfish and self-centered. It is now claimed that this proportion has increased. A sample of 3,000 women shows that 1,260 agree with this statement. Can the statistician conclude that more than 40% of women felt that men are basically selfish and self-centered? Use ά = 0.05. A health spa advertised a weight-reducing program and claimed that the average participant in the program loses more than 5 kg. A random sample of 10 participants has the following weights before and after the program. At the 5% level of significance, test his claim. Before 80, 78, 75, 86, 90, 87, 95, 78, 86, 90 After 76, 75, 70, 80, 84, 83, 91, 72, 83, 83…You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 40 bacteria reveals a sample mean of ¯x=64x¯=64 hours with a standard deviation of s=4.2s=4.2 hours. You would like to estimate the mean lifespan for this species of bacteria to within a margin of error of 0.4 hours at a 95% level of confidence. What sample size should you gather to achieve a 0.4 hour margin of error? Round your answer up to the nearest whole number.
- You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 35 bacteria reveals a sample mean of ¯x=74x¯=74 hours with a standard deviation of s=4.2s=4.2 hours. You would like to estimate the mean lifespan for this species of bacteria to within a margin of error of 0.4 hours at a 95% level of confidence. What sample size should you gather to achieve a 0.4 hour margin of error? Round your answer up to the nearest whole number.You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 30 bacteria reveals a sample mean of ¯x=66x¯=66hours with a standard deviation of s=5.4s=5.4hours. You would like to estimate the mean lifespan for this species of bacteria to within a margin of error of 0.75 hours at a 99% level of confidence.What sample size should you gather to achieve a 0.75 hour margin of error? Round your answer up to the nearest whole number.n = bacteriaYou are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly less than 0.24. Thus you are performing a left-tailed test. Your sample data produce the test statistic z=−2.665z=-2.665. Find the p-value accurate to 4 decimal places.
- To evaluate the effect of a treatment, a sample is obtained from a population with a mean of 20 and the treatment is administered to the individuals in the sample. After treatment, the sample mean is found to be X = 17.7 with a standard deviation of ô = 3. (a) If the sample consists of N = 16 individuals, are the data sufficient to conclude that the treatment decreases scores? (b) If the sample consists of N = 36 individuals, are the data sufficient to conclude that the treatment decreases scores? (c) Comparing your answers for parts (a) and (b), how does the size of the sample influence the size of the obtained Bayes factor?A sample of size 31 was gathered from high school seniors to estimate how many intended to attend the state university. It is known that the proportion of the population answering "yes" was 0.7. What are the mean and standard deviation, and standard error of the mean of this sample? mean = E(p) = %3D standard error = SD(p) (accurate to 3 decimal places)An SRS of 350350 high school seniors gained an average of x¯=24.85 points in their second attempt at the SAT Mathematics exam. Assume that the change in score has a Normal distribution with standard deviation σ=48.83. We want to estimate the mean change in score ?μ in the population of all high school seniors. (a) Using the 68 – 95 – 99.7 Rule or the ?-z-table (Table A), give a 95% confidence interval (?,?)(a,b) for ?μ based on this sample. (Enter your answers rounded to three decimal places. If you are using CrunchIt, adjust the default precision under Preferences as necessary. See the instructional video on how to adjust precision settings.)