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length life with normal distribution, and a standard deviation of o = 10 hours. A sample of size n = 100 is obtained, and its sample mean is calculated to be 400 hours. Find the 99% confidence interval for the average length life fl. = 397.424 U < 402.576 x invalid interval notation. Find the upper 99% bound for the average length life μl. 402.576 397.424 x invalid interval notation. Find the lower 99% bound for the average length life fl. x invalid interval notation. Give your answer as intervals. Use - and too if needed

length life with normal distribution, and a standard deviation of o = 10 hours. A sample of size n = 100 is obtained, and its sample mean is calculated to be 400 hours. Find the 99% confidence interval for the average length life fl. = 397.424 U < 402.576 x invalid interval notation. Find the upper 99% bound for the average length life μl. 402.576 397.424 x invalid interval notation. Find the lower 99% bound for the average length life fl. x invalid interval notation. Give your answer as intervals. Use - and too if needed

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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An electrical firm manufactures light bulbs that have a length life with normal distribution, and a standard deviation of a = 10 hours. A sample of size n 100 is obtained, and its sample mean is calculated to be 400 hours. = Find the 99% confidence interval for the average length life μl. = 397.424 < u < 402.576 x invalid interval notation. Find the upper 99% bound for the average length life u. 402.576 397.424 X invalid interval notation. Find the lower 99% bound for the average length life . x invalid interval notation. Give your answer as intervals. Use - and +∞ if needed.
Transcribed Image Text:An electrical firm manufactures light bulbs that have a length life with normal distribution, and a standard deviation of a = 10 hours. A sample of size n 100 is obtained, and its sample mean is calculated to be 400 hours. = Find the 99% confidence interval for the average length life μl. = 397.424 < u < 402.576 x invalid interval notation. Find the upper 99% bound for the average length life u. 402.576 397.424 X invalid interval notation. Find the lower 99% bound for the average length life . x invalid interval notation. Give your answer as intervals. Use - and +∞ if needed.
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