4. The electric field near a charged, long, narrow, wire (think of monofilament, fishing line) washinted at in homework 01 by solving a source charge integration problem. The electric fieldto the side of a charged, narrow wire (or rod) of length 2a was found to be1xdyQ2a1B = 47², (^) (2² +2² ²2² = 425, (204) (2√2² + 2²Απερ(1).3/2ATTEa1Απεsimpler expression E =Qo(x√x² + a²Then, one can take the limit as the length a tends toward infinity to obtain the much20₁2TE Tr. Here, we have transitioned from a distance r to the sideof the wire (in the x-y plane) to a more general, radial distance out from the wire in anyplane (not just the z-y plane). This same simpler equation can be very easily obtained byapplying Gauss' Law using an appropriate Gaussian surface that surrounds part of aninfinitely long, charged wire. Find this derivation (in a book or online) and rewrite it below.Add verbal explanations to take the reader through the derivation, equation by equation.

Answered: Then, one can take the limit as the…

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