An infinitely long, solid insulating cylinder with radius Ra is placed concentric within a conducting cylindrical shell of inner radius R, and outer radius Re. The inner cylinder has a uniform volume charge density +[p], and the outer cylinder has a net linear charge density of -3121. Assume IpR²> [32] for all parts.
An infinitely long, solid insulating cylinder with radius Ra is placed concentric within a conducting cylindrical shell of inner radius R, and outer radius Re. The inner cylinder has a uniform volume charge density +[p], and the outer cylinder has a net linear charge density of -3121. Assume IpR²> [32] for all parts.
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![An infinitely long, solid insulating cylinder with radius Ra is placed concentric within a
conducting cylindrical shell of inner radius R₂ and outer radius Re. The inner cylinder has a uniform
volume charge density +lpl, and the outer cylinder has a net linear charge density of -3121.
Assume IpR²l> 132] for all parts.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1e65d3f-3c77-4e7f-88fc-bf17213b1ce1%2F4be792aa-579a-4512-ae1d-b71fa80d504f%2Fgfkxuhl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An infinitely long, solid insulating cylinder with radius Ra is placed concentric within a
conducting cylindrical shell of inner radius R₂ and outer radius Re. The inner cylinder has a uniform
volume charge density +lpl, and the outer cylinder has a net linear charge density of -3121.
Assume IpR²l> 132] for all parts.
![Let r denote the radial distance from the center of the insulating cylinder. To solve Gauss' law in
all space, there are four (4) regions to consider. The result for the electric field E(r) in regions 1-
III are given below
E₁(r) =
E (T) =E₁ (1) =
-rf
2€0
pR²1
I claim Ey (r) is
260 T
E(r) = 0
r< Ra
f Ra <r < R
Rp <r < Re
Using Gauss' law, derive the expression for E(r) in region IV, where r > Rc.
3λ
E₁v (T) = (1-PR)
2€0
Make a statement on the term in parenthesis in E (1).
r](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1e65d3f-3c77-4e7f-88fc-bf17213b1ce1%2F4be792aa-579a-4512-ae1d-b71fa80d504f%2Fu0hqyzs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let r denote the radial distance from the center of the insulating cylinder. To solve Gauss' law in
all space, there are four (4) regions to consider. The result for the electric field E(r) in regions 1-
III are given below
E₁(r) =
E (T) =E₁ (1) =
-rf
2€0
pR²1
I claim Ey (r) is
260 T
E(r) = 0
r< Ra
f Ra <r < R
Rp <r < Re
Using Gauss' law, derive the expression for E(r) in region IV, where r > Rc.
3λ
E₁v (T) = (1-PR)
2€0
Make a statement on the term in parenthesis in E (1).
r
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