The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that we can still apply Gauss's law to a Gaussian surface that is entirely within an insulator by replacing the right-hand side of Gauss's law, Qin/€0, with Qin /s, where & is the permittivity of the material. (Technically, & is called the vacuum permittivity.) Suppose that a 75 nC point charge is surrounded by a thin, 32-cm-diameter spherical rubber shell and that the electric field strength inside the rubber shell is 2500 N/C. Part A What is the permittivity of rubber? € = IVE ΑΣΦ xa Submit Xb 7 √x vx x x Previous Answers Request Answer IXI ? X.10n X C²/N-m²

The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that we can still apply Gauss's law to a Gaussian surface that is entirely within an insulator by replacing the right-hand side of Gauss's law, Qin/€0, with Qin /s, where & is the permittivity of the material. (Technically, & is called the vacuum permittivity.) Suppose that a 75 nC point charge is surrounded by a thin, 32-cm-diameter spherical rubber shell and that the electric field strength inside the rubber shell is 2500 N/C. Part A What is the permittivity of rubber? € = IVE ΑΣΦ xa Submit Xb 7 √x vx x x Previous Answers Request Answer IXI ? X.10n X C²/N-m²

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

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The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside
an insulator. It turns out that we can still apply Gauss's law to a Gaussian surface that is
entirely within an insulator by replacing the right-hand side of Gauss's law, Qin/€0, with
Qin /ɛ, where & is the permittivity of the material. (Technically, is called the vacuum
permittivity.) Suppose that a 75 nC point charge is surrounded by a thin, 32-cm-diameter
spherical rubber shell and that the electric field strength inside the rubber shell is
2500 N/C.
Part A
What is the permittivity of rubber?
ε =
[5] ΑΣΦ
xa Xb
Submit
√x vx X
x
Previous Answers Request Answer
IXI
?
X.10n
C²/N.m²

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