The Yonkers integrity auditor examined the weights of Oreo cookies for 12 randomly selected Oreo cookies The sample gave the following results in grams:11.22,11.35,11.50,11.73,11.42,11.15,11.43,11.65,11.56,11.06,10.82,10.99Weights of Oreo cookies are known to be normally distributed, with an unknown mean of μ and an unknown standard deviation o.a) Calculate the sample mean for this data.b) Calculate the sample standard deviation for this data.c) Calculate the sample median for this data.d) Calculate the sample range for this data. (One number)e) Calculate the sample variance for this data.f) Suppose W has a t distribution with 11 degrees of freedom. If P(W > t) = .05 then what is t?g) Suppose W has a t distribution with 11 degrees of freedom. If P(W

The given information is as followsX is the random variable that follows a normal distribution with…

Answered: The Yonkers integrity auditor examined…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Suppose you have two samples with the following values: Sample 1: 2, 8, 6, 5, 4, 7, 5, 9, 6 Sample 2: 3, 5, 4, 8, 7, 5, 5, 7,6 For Sample 1, what are the values for: Mean Median Mode Standard Deviation Variance
The cost of unleaded gasoline in the Bay Area once followed an unknown distribution with a mean of $ 4.87 and a standard deviation of $ 0.05. A sample of 15 Bay Area gas stations are randomly chosen. We are interested in the average cost of gasoline for the 15 service stations. The distribution to use for the average cost of gasoline for the 15 service stations is: Select one: a. N (4.87, 0.0129) b. N (0.3247, 0.0006) c. N (4.87, 0.0033) d. N (4.87, 0.0002) e. N (0.3247, 0.0033)
Q.1.1 Consumer testing services compared public opinion on gas ovens and electric ovens. They asked participants to rate their opinions using a scale from 1 to 10. A random sample of 220 households were interviewed. The descriptive statistics are as follows: MeanStandard deviation Sample size respectively Gas Ovens mean7.45 standars deviation3.32 sample size220 Electric Ovens mean8.85 standard deviation4.14 sample size220 Q.1.1.1 Calculate the standard deviation of the difference between the mean opinion scores of gas ovens and electric ovens. Q.1.1.2 The analyst concluded that there was 50% probability that the sample mean of opinion scores of gas ovens is smaller than that of electric ovens. He used z-transformations and got z = -3.9. Calculate the z value using information in the table to check if the value of -3.9 used by the analyst was correct.
A study reported that finger rings increase the growth of bacteria on health-care workers’ hands. Research suggests that 31 percent of health-care workers who wear rings have bacteria on one or both hands. Suppose that independent random samples of 100 health-care workers wearing rings is selected. What is the standard deviation of the sampling distribution of the sample proportions of health-care workers having bacteria on one or both hands? A. 100 B. 0.0462 C. 0.69
Dr. Graham is interested in determining if middle-aged adults use text messaging more or less frequently than the general population. Dr. Graham collects information on text messaging from a random sample of 50 adults ages 25 to 44. Dr. Graham finds that these individuals send or receive an average of 68 text messages per day. Using the population mean (and standard deviation) of 41.5 texts per day (34 texts per day), determine whether adults in this age group use text messaging more than the general public.
calculate ss variance and standard deviation for the following population of N=5 scores: 2,13,4,10,6
Unoccupied seats on flights cause airlines to lose revenue. As an intern in the finance department for Sunrise Airways, Garrett is tasked with estimating the average number of unoccupied seats per flight over the past year. To accomplish this, the records of 320 flights are randomly selected and the number of unoccupied seats is noted for each of the sampled flights. The sample mean is 15.6 seats and the standard deviation is 4.6 seats. Construct a 99% confidence interval for the population mean number of unoccupied seats per flight during the past year. If necessary, round results to 1 decimal places.
The following are the normalized levels of a critical protein in 12 samples of blood: 8.2 , 4.7 , 10.3 , 11.7 , 18.3 , 5.9 , 3.8 , 18.9 , 7.6 , 14.2 , 9.8 , 16.4 Compute the sample mean, the sample median, and the sample standard deviation.
A sample of 19 elements was used to construct a 99% confidence interval for the population variance, the chi-square value (s) used for this test are: Select one: a. 7.015 to 34.805 b. 7.633 to 36.191 O c. 6.844 to 38.582 d. 6.265 to 37.156 ge Next page ETIVITY NEXT ACTIVITY Jump to. Midterm 1
A study involving the economic burden of congestive heart failure found that the lengths of hospital stays for patients are not normally distributed with a mean of 7.8 days and a standard deviation of 9.1 days. A random sample of size 40 is taken. Which of the following best describes the sampling distribution of *? Select one: a. Normal b. Approximately normal C. Unknown
Unoccupied seats on flights cause avrlines to lose revenue. As an intern in the finance department for Golden Ticket Airlines, Carlos is tasked with estimating the average number of unoccupied seats per flight over the past year. To accomplish this, the records of 222 flights are randomly selected and the number of unoccupied seats is noted for each of the sampled flights. The sample mean is 18 seats and the standard deviation is 2.5 seats. Construct a 80% confidence interval for the population mean number of unoccupied seats per flight during the past year. If necessary, round results to 1 decimal places.
Unoccupied seats on flights cause airlines to lose revenue. As an intern in the finance department for Skyline Airways, Rebecca is tasked with estimating the average number of unoccupied seats per flight over the past year. To accomplish this, the records of 231 flights are randomly selected and the number of unoccupied seats is noted for each of the sampled flights. The sample mean is 14.7 seats and the standard deviation is 3.4 seats.Construct a 90% confidence interval for the population mean number of unoccupied seats per flight during the past year.If necessary, round results to 1 decimal places.

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