, Suppose W has at distribution with 10 degrees of freedom. If P(W < t) = .05 then what is t? I Calculate the 9sth percentile of a standard normal distribution. Compute an 90% confidence interval for u using your answers above.
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- Find the Critical Values of the t- Distribution needed for a 95% confidence interval for the mean, with df=6. (that is find txα/2). Just type in the positive value, to 3 decimal places, in the text box below.A simple random sample of 10 subjects finds that the sample mean is 56 and the standard deviation is 4. Find the 98% confidence interval for u. Display the result in interval notation. You must round your result to decimal places. Remember that the information you have is from a small sample, you must use the t distribution. Remember that critical values can be calculated in EXCEL using the degrees of freedom (n-1) and the level of significance (I - C) as a function of T.INV 2T (Level of Significance, Degrees of Freedom) Select one: a. The interval is: (53,057, 58,943) b. The range is: (53,521, 58,479). c. The interval is: (51,080, 60,920) d. The interval is: (51.991, 60.009) e. The interval is: (52,431, 59,569)Lorraine computed a confidence interval for μ based on a sample of size 41. Since she did not know σ, she used s in her calculations. Lorraine used the normal distribution for the confidence interval. Are Lorraine's methods correct? Explain.
- Data indicates that adolescent girls tend to experience a drop in self-esteem. To evaluate this result, a researcher obtains a sample of N = 36 adolescent girls, all 13 years old. A self-esteem measure is administered to each participant and the average score for the sample is X =68. It is known that the distribution of self-esteem scores for the population of pre-teen girls is normal with mean 80 and standard deviation 10. (a) Compute a 95% confidence interval for µ, the population mean self-esteem score for adolescent girls. (b) Compute Cohen’s d to estimate the size of the described effect. (c) Perform a hypothesis test to decide whether the mean self-esteem score for adolescent girls is significantly different from the mean self-esteem score for pre-teen girls. (d) Compute and interpret a Bayes factor for the model (either H0 or H1) with the best predictive adequacy. (e) Compute and interpret the posterior model probability for the winning model chosen in part (d).Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value ta/2. (b) find the critical value za/2. or (c) state that neither the normal distribution nor the t distribution applies. Here are summary statistics for randomly selected weights of newborn girls: n=D156, x 29.3 hg, s = 7.7 hg. The confidence level is 90%.Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value ta/2. (b) find the critical value z/2, or (c) state that neither the normal distribution nor the t distribution applies. The confidence level is 95%, o is not known, and the histogram of 62 player salaries (in thousands of dollars) of football players on a team is as shown.
- The National Assessment of Educational Progress (NAEP) includes a mathematical test for eighth-grade students. Scores on the test range from 0 to 500. Suppose that you give the NAEP test to an SRS of 2500 eighth-graders from a large population in which the scores have mean u = 282 and standard deviation o = 110. The mean x will vary if you take repeated samples. Suppose that we computed a 90% confidence interval for u. Which is true? This 90% confidence interval could have either a smaller or a larger margin of error than the 95% confidence interval. This varies from sample to sample. This 90% confidence interval would have a smaller margin of error than the 95% confidence interval. This 90% confidence interval would have a larger margin of error than the 95% confidence interval. This 90% confidence interval would have the margin of error as the 95% confidence interval.Give a 99.8% confidence interval, for µ1 - µ2 given the following information. 2.04, s1 = 0.39 20, ã1 60, x2 = 2.37, 82 - 0.7 n2 Use Technology Rounded to 2 decimal places.Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.t Suppose a small group of 20 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with o = 0.32 gram. (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) O normal distribution of weights Oo is known O n is large O o is unknown O uniform distribution of weights (c) Interpret your results in the context of this problem. O The probability that this interval contains the true average weight of Allen's hummingbirds is 0.20. O we are 80% confident that the true average weight of Allen's hummingbirds falls…
- Assume the finishing times for 5K male races are approximately normal with µ = 28 minutes andstandard deviation σ = 4.27 minutes. Find the probability that a runner takes less than 26 minutes to finish a 5K race. Compute the third quartile Q3 of the distribution. How fast are the fastest 15% of male 5K runners?The following data represent the length of time, in days, to recovery for patients randomly treated with one of two medications to ciear up severe bladder infections. Find a 95% confidence interval for the difference u,-H, between in the mean recovery times for the two medications, assuming normal populations with equal variances. Medication 1 x, 13 s = 14 s =1.6 n, = 14 Medication 2 n211 X2= 16 Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table ofcritical values of the t-distribution The confidence interval isAssume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value to/2. (b) find the critical value Zα/2, or (c) state that neither the normal distribution nor the t distribution applies. Here are summary statistics for randomly selected weights of newborn girls: n=218, x = 30.4 hg, s = 7.6 hg. The confidence level is 99%. ... Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. ta/2= (Round to two decimal places as needed.) OB. Za/2 (Round to two decimal places as needed.) OC. Neither the normal distribution nor the t distribution applies.SEE MORE QUESTIONS