Given the 4 categories and distribution, apply the Goodness-of-fit test for the claim that the 4 categoriesoccur with the following distribution:0.25: PB= 0.25; pc = 0.4; pp = 0.1Ho: PACategoryObserved ExpectedFrequency Frequency22.5A2822.5B13C29D2020a. Complete the table for the expected frequencies.b. What is the chi-square test statistic for this data? Round to three decimal places.c. What is the p-value? Round to four decimal places.p-value-d. Testing the claim at a a=0.025 significance level, what would be the conclusion of this hypothesistest?Reject the Null Hypothesis.O Fail to reject the Null Hypothesis.

Answered: Given the 4 categories and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Before the furniture store began its ad campaign, it averaged 123 customers per day. The manager is investigating if the average is larger since the ad came out. The data for the 11 randomly selected days since the ad campaign began is shown below: 110, 154, 108, 112, 151, 146, 144, 130, 138, 129, 142 Assuming that the distribution is normal, what can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: vSelect an answer H1: ?V Select an answer V c. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value = e. The p-value is ?V a f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) the null hypothesis. O The data suggest the populaton mean is significantly more than 123 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of customers since the…
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This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
For a Chi-Squared Goodness of Fit Test about a distribution that has the following characteristics: Category 1: 50% Category 2: 15% Category 3: 20% Category 4: 15% complete the table. Round to the fourth as needed. Categories 1 2 3 4 Observed Frequency 295 82 109 60 Expected Frequency
For the following distribution of z-scores location, what is the portion in the tail? z = 2.00 Answer: z = .50 Answer: %3D z = -1.50 Answer: z = -1.00 Answer: z = -.25 Answer:
Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $10,500? To decide, you select a random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ =$6511 and 2 = $6192. At a = 0.01, what should you conclude? Entry level architects Entry level architects in Denver, CO x₁ = 58,300 n₁ = 39 In Lincoln, NE x2 = 54,240 n2 = 30 What are the null and alternative hypotheses for this test? OA. Ho: H₁₂ = 10,500 Ha: H₁-H2*10,500 OD. Ho: P₁-H2>10,500 Ha: H1-H₂s 10,500 Calculate the standardized test statistic. z= (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) What can you conclude about the data? OB. Ho: H1 H2S 10,500 Ha H1-H2>10,500 OC. Ho: H1 H2210,500 Ha H1-H2 <10,500 OE. Ho: H1 H2*10,500 Ha: 1-2=10,500 OA. Reject Ho. At the 1% level of significance, there is…
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