Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $10,500? To decide, you select a random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ =$6511 and 2 = $6192. At a = 0.01, what should you conclude? Entry level architects Entry level architects in Denver, CO x₁ = 58,300 n₁ = 39 In Lincoln, NE x2 = 54,240 n2 = 30 What are the null and alternative hypotheses for this test? OA. Ho: H₁₂ = 10,500 Ha: H₁-H2*10,500 OD. Ho: P₁-H2>10,500 Ha: H1-H₂s 10,500 Calculate the standardized test statistic. z= (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) What can you conclude about the data? OB. Ho: H1 H2S 10,500 Ha H1-H2>10,500 OC. Ho: H1 H2210,500 Ha H1-H2 <10,500 OE. Ho: H1 H2*10,500 Ha: 1-2=10,500 OA. Reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $10,500. OB. Reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $10,500. OC. Fail to reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $10,500. OD. Fail to reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $10,500. OF. Ho: H1 H21 <10,500 Ha: H1-H₂≥10,500
Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $10,500? To decide, you select a random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ =$6511 and 2 = $6192. At a = 0.01, what should you conclude? Entry level architects Entry level architects in Denver, CO x₁ = 58,300 n₁ = 39 In Lincoln, NE x2 = 54,240 n2 = 30 What are the null and alternative hypotheses for this test? OA. Ho: H₁₂ = 10,500 Ha: H₁-H2*10,500 OD. Ho: P₁-H2>10,500 Ha: H1-H₂s 10,500 Calculate the standardized test statistic. z= (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) What can you conclude about the data? OB. Ho: H1 H2S 10,500 Ha H1-H2>10,500 OC. Ho: H1 H2210,500 Ha H1-H2 <10,500 OE. Ho: H1 H2*10,500 Ha: 1-2=10,500 OA. Reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $10,500. OB. Reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $10,500. OC. Fail to reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $10,500. OD. Fail to reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $10,500. OF. Ho: H1 H21 <10,500 Ha: H1-H₂≥10,500
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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