I am stumped and can't figure out what I am missing here could you help me out with this? The yield stress for a zirconium-magnesium alloy is σy = 15.3 ksi. A machine part ismade of this material and a critical point in the material is subjected to in-plane principalstresses σ and σ2 = -0.6 01-▾Part ADetermine the magnitude of σ that will cause yielding according to the maximum-shear-stress theory.Express your answer using three significant figures and include the appropriate units.01 = 25.5?ksiSubmitPrevious Answers Request Answer× Incorrect; Try Again

Given information:Yield stress, σy=15.3ksiPrincipal stresses: σ1 and σ2=−0.6σ1Maximum Shear…

Answered: The yield stress for a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The state of stress acting at a critical point on a wrench is shown in the figure. Pi P2 - 340 MPa Part A خ == .0 P₁ OY = Value P. Determine the smallest yield stress for steel that might be selected for the part, based on the maximum shear stress theory. Express your answer to three significant figures and include appropriate units. Units P110 MPa and EDIT ? C
The state of stress acting at a critical point on a wrench is shown in the figure. P = 170 MPa and P, = 290 MPa P Part A Determine the smallest yield stress for steel that might be selected for the part, based on the maximum shear stress theory. Express your answer to three significant figures and include appropriate units. 336.155 MPа oy =
In (Figure 1), y = 13.9 ksi. Figure 10 ksi < 20 ksi 1 ▼ Determine the principal stresses. Specify the orientation of the element. Express your answers, separated by commas, to three significant figures. 01, 02, 0pl = Submit Part B T in-plas 195| ΑΣΦ | it | vec Request Answer Submit =, avg=, 0,= 1 Request Answer Determine the maximum in-plane shear stress and average normal stress. Specify the orientation of the element. Express your answers, separated by commas, to three significant figures. d 195] ΑΣΦ | it Ivec BARC 5 → C ? www. ksi, ksi, (clockwise) ? 0 ksi, ksi, (clockwise)
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The yield stress for a zirconium-magnesium alloy is sY = 15.3 ksi. If a machine part is made of this material and a critical point in the material is subjected to in-plane principal stresses s1 and s2 = -0.5s1, determine the magnitude of s1 that will cause yielding according to the maximum shear stress theory.
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The fluctuating stresses listed in the table are found at a critical location of a component made of steel with Se = 40 ksi, Sy = 80 ksi, Sut = 110 ksi and f= 0.87. These stresses are applied on the part within 10 s. What is the accumulative damage of this part? What is the life of the part in hours if this stress pattern continues to repeat for the remained of the part's life? Use Goodman criterion and Miner's rule in your solution. Loading order |Omin o max |Number of cycles -20 30 -10 50 1 3. -30 30 1
A steel with a yield stress of 300 MPa is tested under a state of stress whereσ2 = σ1/2 and σ3 = 0. What is the stress at which yielding occurs if it isassumed that:(a) The maximum-normal-stress criterion holds?(b) The maximum-shear-stress criterion holds?(c) The distortion-energy criterion holds?
Determine the yield strength of a material required such that the component would not fail when subject to the following stresses sigma1 = 2 MPa and sigma 2= -15 MPa sigma 3 = 10 MPa). Use a yield criterion that assumes that yield failure will occur when the maximum shear stress in the complex system becomes equal to the limiting shear strength in a simple tensile test.
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A tension test was performed on a steel specimen having an original diameter of 12.5 mm and gauge length of 50 mm. The data is listed in the table. Plot the stress–strain diagram and determine approximately the modulus of elasticity, the yield stress, the ultimate stress, and the rupture stress. Use a scale of 25 mm = 140 MPa and 25 mm = 0.05 mm/mm. Redraw the elastic region, using the same stress scale but a strain scale of 25 mm = 0.001 mm/mm.
Correctly solve by using correct expression

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