**Educational Website Content: Hypothesis Testing Problem**Title: Analyzing Web Browser Market Share at a University---**Problem Statement:**The worldwide market share for a particular web browser was 20.1% in a recent month. Suppose that a sample of 120 random students at a certain university finds that 30 students use this browser. We aim to evaluate whether the market share for this web browser at the university is greater than the worldwide market share of 20.1%.---**Task (Part a):****At the 0.01 level of significance, is there evidence that the market share for the web browser at the university is greater than the worldwide market share of 20.1%?****Steps to Solve:**1. **Determine the Null and Alternative Hypotheses:** - **Option A:** \( H_0: \pi \neq 0.201 \); \( H_1: \pi < 0.201 \) - **Option B:** \( H_0: \pi = 0.201 \); \( H_1: \pi \neq 0.201 \) - **Correct Option (C):** \( H_0: \pi \le 0.201 \); \( H_1: \pi > 0.201 \) - **Option D:** \( H_0: \pi \neq 0.201 \); \( H_1: \pi = 0.201 \)2. **Calculate the Test Statistic:** Formula for calculating the test statistic \( Z_{\text{STAT}}: \) \[ Z_{\text{STAT}} = \, \text{(Type an integer or a decimal. Round to two decimal places as needed.)} \] ---Note: Ensure your statistical calculations, steps, hypothesis setting, and decision-making process are correct and properly rounded when using this information in practical applications.

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Answered: The worldwide market share for a web…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(a) Determine the null and alternative hypotheses that would be used to test the effectiveness of the marketing campaign. Ho: = μ 56 H₁: μ > 56 (Type integers or decimals. Do not round.) (b) A sample of 884 Americans provides enough evidence to conclude that marketing campaign was effective. Provide a statement that should be put out by the marketing department. O A. There is not sufficient evidence to conclude that the mean consumption of popcorn has risen. B. There is sufficient evidence to conclude that the mean consumption of popcorn has risen. C. There is sufficient evidence to conclude that the mean consumption of popcorn has stayed the same. D. There is not sufficient evidence to conclude that the mean consumption of popcorn has stayed the same.
The worldwide market share for a web browser was 20.4% in a recent month. Suppose that a sample of 100 random students at a certain university finds that 25 use the browser. Complete parts (a) through (d) below. a. At the 0.05 level of significance, is there evidence that the market share for the web browser at the university is greater than the worldwide market share of 20.4%? Determine the null and alternative hypotheses. O A. Ho: 0.204; H₁: = 0.204 (C. B. Ho: T =0.204; Hạ x>0.204 OC. Ho: 20.204; H₁: <0.204 #0.204 O D. H₂: = 0.204; H₁: C Calculate the test statistic. ZSTAT (Type an integer or a decimal. Round to two decimal places as needed.)
Women athletes at a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample of 38 women athletes at the school showed that 23 eventually graduated. Does this indicate that the population proportion of women athletes who graduate from the university is now less than 67%? Use a 10% level of significance. What is the level of significance? (b) State the null and alternate hypotheses. H0: p = 0.67; H1: p > 0.67 H0: p = 0.67; H1: p ≠ 0.67 H0: p < 0.67; H1: p = 0.67 H0: p = 0.67; H1: p < 0.67 What sampling distribution will you use? The Student's t, since np < 5 and nq < 5. The standard normal, since np < 5 and nq < 5. The standard normal, since np > 5 and nq > 5. The Student's t, since np > 5 and nq > 5. What is the value of the sample test statistic? (Round your answer to two decimal places.) Find the P-value of the test statistic. (Round your answer to four decimal places.)…
what is 1. P value 2. Z value 3. Critical value 4. Reject or do not reject 5. State conclusion
I need help solving this problem.
Suppose that the proportion of investors who are risk-averse (that is, try to avoid risk in their investment decisions) is though to be at least 0.7. A financial advisor believes that the proportion is actually less than 0.7. A survey of 35 investors found that 23 of them were risk-averse. Formulate a one-sample hypothesis test for a proportion to test this belief. Determine the null hypothesis, H,, and the alternative hypothesis, H,. Ho H,: (Type integers or decimals. Do not round.) Compute the test statistic. (Round to two decimal places as needed.) Find the p-value for the test. (Round to three decimal places as needed.) State the conclusion at the 0.05 level of significance. The p-value is V the chosen value of a, so the null hypothesis. There is evidence to conclude that the proportion of investors who are risk-averse is not at least 0.7.
The following MINITAB output presents the results of a hypothesis test for a population proportion p. Some of the numbers are missing. Fill in the numbers for (a) through (c). Test and CI for One Proportion: X Test of p = 0.7 vsp < 0.7 X N Sample p 95% Upper Bound z-Value P-Value 0.724021 Variable 345 500 (a) (b) (b) (c) х
The researchers found that 83.3% of students in the sample have rarely or never used the food pantry on campus. We will test whether it is plausible that more than 80% of all students on campus have rarely or never used the campus food pantry. Identify (describe in words) the parameter and include the appropriate symbol. State the null and alternative hypotheses in symbols. Use the One proportion inference applet to create a distribution of 1000 simulated sample statistics (with the “Proportion of successes” option) and include a screenshot below that shows what you entered in the applet as well as the resulting distribution. Check the Summary Statistics box and explain why the values of the mean and SD (SE) make sense according to theory-based methods. Use the applet to find a p-value for this situation. Explain how you do this, and include a screenshot that shows the relevant portion of the applet, including the distribution of simulated sample statistics. State the value of…
8)
8. From a random sample of n = 900 students, 630 of them have attended a particular summer camp. Calculate the 90% confidence interval for the proportion of students attending the summer camp. A. 0.7 +3.8380 B. 0.7 +0.0153 C. 0.7 ± 0.0299 D. 0.7 + 0.0251
Assume that a simple random sample has been selected from a normally distributed population and test the given claim.A researcher wants to test the claim that convicted burglars spend an average of 18.7 months in jail. She takes a random sample of 11 such cases from court files and finds that x = 21.3 months and s = 5.7 months. Test the claim at the 0.05 significance level.State the claim in words: Convicted Burglars spend an average of 18.7 months in jail. Ho μ = 18.7 H1 μ ≠ 18.7 What calculator function is needed? p value = __________ Since p ________ α, ________________________ the null hypothesis. Final conclusion:
In a sample of 950 adults, it is found that 48% are registered to vote in their state . Use a 0.05 significance level to test the claim that less than 50% of all adults are registered to vote for their state. a. Find the test statstic b. Find the Critical value c. Find the p- value d. What is the consclusion about the null hypothesis? e. What is the final conclusion in nontechnical terms? ( use the z table )

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