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- a. State the Null and Alternative Hypotheses and Choose the appropriate statistical test b. Determine the Level of Significance and the Critical Value c. Solve for the computed valueConsider the following hypotheses: Hg: H 2 160 НА: и < 160 The population is normally distributed. A sample produces the following observations: 152 138 151 144 151 142 Conduct the test at the 1% level of significance. (You may find it useful to reference the appropriate table: z table or table) a. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round final answer to 2 decimal places.) Test statisticThe quality department at an electronics company has noted that, historically, 96% of the units of a specific product pass a test operation, 3% fail the test but are able to be repaired, and 1% fail the test and need to be scrapped. Due to recent process improvements, the quality department would like to test if the rates have changed. A recent sample of 500 parts revealed that 474 parts passed the test, 18 parts failed the test but were repairable, and 8 parts failed the test and were scrapped. (You may find it useful to reference the appropriate table: chi-square table or F table) a. Choose the appropriate alternative hypothesis for the test. O At least one of the p; (i=1, 2, 3) differs from its hypothesized value. O All p; (i=1, 2,3) values differ from its hypothesized value. b-1. Compute the value of the test statistic. (Round the intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.) Test statistic b-2 Find the p-value. re to search
- Which of the following is the best decision and conclusion based on the result below? H.: p = 0.10 Ha:p + 0.10 Critical Value: +1.645 Computed Test Statistics: z = 5.61 O a. Since the computed test statistics is less than the critical value, do not reject Ho. Therefore, we conclude that at 0.10 level of significance, there is enough evidence that the population proportion is different from 10%. O b. Since the computed test statistics is less than the critical value, do not reject Ho. Therefore, we conclude that at 0.10evel of significance, there is enough evidence that the population proportion is different from 10%. O c. Since the computed test statistics is greater than the critical value, reject Ho. Therefore, we conclude that at 0.10 level of significance, there is enough evidence that the population proportion is different from 10%. O d. Since the computed test statistics is less than the critical value, reject Ho. Therefore, we conclude that at 0.10 level of significance, there…Assume a significance level of α=0.1 and use the given information to complete parts (a) and (b) below. Original claim: The mean pulse rate (in beats per minute) of a certain group of adult males is 70 bpm. The hypothesis test results in a P-value of 0.0025. a. State a conclusion about the null hypothesis. (Reject H0 or fail to reject H0.) Choose the correct answer below. A. Fail to reject H0 because the P-value is less than or equal to α. B. Reject H0 because the P-value is less than or equal to α. C. Reject H0 because the P-value is greater than α. D. Fail to reject H0 because the P-value is greater than α. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. The mean pulse rate (in beats per minute) of the group of adult males is 70 bpm. B. There is sufficient evidence to warrant rejection of the claim that the…Suppose the national average dollar amount for an automobile insurance claim is $777.86. You work for an agency in Michigan and you are interested in whether or not the state average is less than the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≥ 777.86, Alternative Hypothesis: μ < 777.86. You take a random sample of claims and calculate a p-value of 0.0232 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance. Question 9 options: 1) The true average claim amount is significantly different from $777.86. 2) The true average claim amount is significantly less than $777.86. 3) The true average claim amount is significantly higher than $777.86. 4) We did not find enough evidence to say the true average claim amount is less than $777.86. 5) The true average claim…
- 4. (This problem is required to submit) Consider the following hypothesis test. H:µ = 20 H.:µ + 20 A sample of 200 items will be taken and the population standard deviation is o = 10. Use a = 0.05. Compute the probability of making a Type II error if the population mean is: a. u =18.0 (33%) (Note: without calculation process, no credit) b. µ= 22.5(33%) (Note: without calculation process, no credit) c. µ=21.0 (34%) (Note: without calculation process, no credit)Consider the following hypothesis test: H0: mu=15 Ha: mu not = to 15 A sample of 40 provided a sample mean of 14.18 . The population standard deviation is 5 . Enter negative value as negative number. a. Compute the value of the test statistic (to 2 decimals). b. What is the p-value (to 4 decimals)? Use the value of the test statistic rounded to 2 decimal places in your calculations. c. Using a=.05, can it be concluded that the population mean is not equal to 15 ?- Select your answer -YesNoItem 3 Answer the next three questions using the critical value approach. d. Using a=.05 , what are the critical values for the test statistic? (+ or -) (to 2 decimals) State the rejection rule: RejectH0 if z is - Select your answer -greater than or equal to greater than less than or equal to less than equal to not equal to the lower critical value and is - Select your answer -greater than or equal to greater than less than or equal to less than equal to not equal to the upper critical value. Can…The claim is that for 8 AM body temperatures of males, the mean is less than 98.6°F. The sample size is n = 36 and the test statistic is t= -3.675. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.01. State the null and alternative hypotheses. Ho: HV H₁: p V (Type integers or decimals. Do not round. Do not include the degree symbol in your answer.) The test statistic is. (Round to two decimal places as needed.) The P-value is. (Round to three decimal places as needed.) Based on the P-value, there ▼sufficient evidence at a significance level of 0.01 to G ▼the claim that for 8 AM body temperatures of males, the mean is less than 98.6°F.
- 16) Answer (T/F) true or false: a- The alternative hypothesis is stated in terms of a sample statistic. b- a large P-value indicates strong evidence against Ho. c- If there is sufficient evidence to reject Ho at a=0.10, then there is sufficient evidence to reject it also at a=0.05. d- If the population mean is known, there is no reason to run a hypothesis test on the population mean. e- The P-value is usually chosen before an experiment is conducted. f- A well-planned test of significance should result in a statement either that Ho is true or that it is false.I just need x2 & p-valueUse a t-test to test the claim about the population mean μ at the given level of significance a using the given sample statistics. Assume the population is normally distributed. Claim: μ #25; x = 0.01 Sample statistics: x= 28.7, s=4.9, n = 13 What are the null and alternative hypotheses? Choose the correct answer below. O A. Ho: H=25 H₂: μ#25 OB. Ho: H≤25 H₂: μ>25 O C. Ho: μ ≥25 H₂: μ<25 O D. Ho: μ#25 H₂:μ=25 What is the value of the standardized test statistic? The standardized test statistic is (Round to two decimal places as needed.) What is the P-value of the test statistic? P-value= (Round to three decimal places as needed.) Decide whether to reject or fail to reject the null hypothesis. O A. Fail to reject Ho. There is not enough evidence to support the claim. OB. Reject Ho. There is not enough evidence to support the claim. O C. Fail to reject Ho. There is enough evidence to support the claim. OD. Reject Ho. There is enough evidence to support the claim.