The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical justification. 24 V 250 ΜΩ • 250 ΜΩ Fig. Q1(c) V voltmeter
The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical justification. 24 V 250 ΜΩ • 250 ΜΩ Fig. Q1(c) V voltmeter
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Transcribed Image Text:The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement
was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical
justification.
24 V
250 ΜΩ
• 250 ΜΩ
Fig. Q1(c)
V voltmeter
Expert Solution

Step 1
If voltage is not connected then equation voltage is decided due to equal resistance ( By voltage divider rule).
That is in absence of voltmeter each resister has same resistance of 12 volts.
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