The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical justification. 24 V 250 ΜΩ • 250 ΜΩ Fig. Q1(c) V voltmeter
The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical justification. 24 V 250 ΜΩ • 250 ΜΩ Fig. Q1(c) V voltmeter
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Question
![The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement
was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical
justification.
24 V
250 ΜΩ
• 250 ΜΩ
Fig. Q1(c)
V voltmeter](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F82f06837-9829-4941-a094-d7707205fdf0%2Fd4d1cad1-c12c-437f-854f-557f3e2641c5%2Fate8ftb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement
was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical
justification.
24 V
250 ΜΩ
• 250 ΜΩ
Fig. Q1(c)
V voltmeter
Expert Solution
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Step 1
If voltage is not connected then equation voltage is decided due to equal resistance ( By voltage divider rule).
That is in absence of voltmeter each resister has same resistance of 12 volts.
Step by step
Solved in 4 steps with 1 images
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