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The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical justification. 24 V 250 ΜΩ • 250 ΜΩ Fig. Q1(c) V voltmeter

The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical justification. 24 V 250 ΜΩ • 250 ΜΩ Fig. Q1(c) V voltmeter

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The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical justification. 24 V 250 ΜΩ • 250 ΜΩ Fig. Q1(c) V voltmeter
Transcribed Image Text:The voltmeter in Fig. Q1(c) has a lead-to-lead resistance of 10 MS2. Its output for this measurement was found to be 0.8889 V. Describe the reason for this unexpected output, supported by numerical justification. 24 V 250 ΜΩ • 250 ΜΩ Fig. Q1(c) V voltmeter
Expert Solution
Step 1

If voltage is not connected then equation voltage is decided due to equal resistance ( By voltage divider rule).

That is in absence of voltmeter each resister has same resistance of 12 volts.

 

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