The void ratio of a clay sample A decreased from 0.572 to 0.505 under a change in pressure from 122 to 180 kN/m2. The void ratio of another sample B decreased from 0.61 to 0.557 under the same increment of pressure. The thickness of sample A was 1.5 times that of B. Nevertheless, the time taken for 50% consolidation

Q: A cu test was performed on a 3.5cm diameter sand sample. A confining pressure of 2.0 kg/cm2 was…

A:

Q: During an oedometer test on a specimen of saturated clay, the thickness of the specimen decreased…

A: Oedometer test: This is a geotechnical investigation used for measuring properties of consolidation…

Q: 11.4 Organic soils are typically characterized by high void ratio, low specific gravity, and high…

A: Geotechnical designing is significant on the grounds that it forestalls entanglements before they…

Q: consolidated tri-axial test was conducted on a normally consolidated clay. The results were as…

A:

Q: Experimental data for clay specimen obtained initial values of e1 = 1.12 and P1 = 90 kPa, and final…

A: Given- e1 = 1.12 e2 = 0.90 P1 = 90 kPa P2 = 460 kPa To Find -  Coefficient of volume…

Q: undrained triaxial test was conducted on a normally consolidated clay sample and the results are as…

A:

Q: The results of two consolidated-drained test triaxial tests on a clay are given below: Specimen No.…

A:

Q: Calculate the pore volume compressibility of a sandstone sample under confining pressure of 5000…

A: Given data: Confining pressure Psig Cumulative pore volume reduction cc 1000 0.122 2000 0.162…

Q: A saturated clay sample in an oedometer is under vertical pressure of 120 kPa and is at a normally…

A:

Q: The following results were obtained from a set of consolidation test on a specimen of a clay sample…

A: Given Data Thickness of clay layer, H0 = 4.8 m Initial thickness of sample, h0 =19.6 mm…

Q: A CU triaxial test was carried out on a silty clay that was isotopically consolidated using a cell…

A:

Q: The table below contains data obtained from 2 CU triaxial tests on similar clay specimens. Specimen…

A:

Q: A consolidated drained (CD) triaxial test was carried out on a normally consolidated clay. The…

A: According to given data  A consolidated drained (CD) triaxial test was carried out on a normally…

Q: Following are the results of a laboratory consolidation test on a sample of undis- turbed clay…

A: Compression index is normally the variation of void ratio from the replace of effective stress…

Q: The consolidation test of a clay sample taken from a 2 m thick normally consolidated clay soil layer…

A:

Q: Three consolidated-undrained tri-axial tests were performed on samples retrieved from a 4 meter…

A: For the test 1 -  Value of σ'3σ'3 = σ3 - ∆udf⇒σ'3 = 80 - -12⇒σ'3 = 92 KNm2   Value of σ'1σ'1 = σ'3 +…

Q: a）For clays, the failure line (one that connects the peak failure stresses) in the normally…

A: A)Cohesion is the stress of binding together, in soil mechanics the cohesion means shear strength…

Q: uestion-2: In an Oedometer test on a 20 mm thick sample of saturated clay taken from a site, 50%…

A:

Q: A consolidated-undrained tri-axial test was conducted on a normally consolidated clay sample and the…

A: Determine the drained friction angle of the soil. Compute the deviator stress (kPa) at failure

Q: 5. Triaxial tests were conducted on undisturbed samples of clay under CU conditions. Data from the…

A:

Q: 24.A series of consolidated, undrained triaxial tests were carried out on specimens of urated clay…

A: Given:- Confining pressure(kPa) Deviator stress(kPa) Pore Water Pressure(kPa) 150 192 80 300…

Q: A triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure…

A: Given Data:In a triaxial testNormal stress on failure plane = 6100 psfShear stress on gailure plane…

Q: The water content of a sample of saturated soil at a mean effective stress of 10 kPa is 85%. The…

A:

Q: 423 8, The results of three consolidated-undrained particular soil are: Test no. a (kPa) a-a at peak…

A: Calculate the values and tabulate them Specimen σ3(kPa) σd(kPa) σ1=σ3+σd U σ1' σ3' 1 200 244…

Q: A sample of saturated normally consolidated clay was isotropically consolidated to a cell pressure…

A:

Q: 9. A consolidated drained test was carried out on a sandy clay under a cell pressure of 250 kPa. A…

A: A consolidated trained test was carried out on a sandy clay under a cell pressure of 250 kPa. A…

Q: (From Chapter 7) 6. A sample of normally consolidated clay was obtained by a Shelby tube sampler…

A: e p (tons/ft2) 1.72 0.250 1.70 0.500 1.64 1.00 1.51 2.00 1.34 4.00 1.15 8.00 0.95…

Q: Required a. The compression index of the clay b. The swelling index of the clay C. The height of…

A: The height of clay specimen, H = 25 4 mmPerconsolidation pressure v1 = 150 kpaEffective vertical…

Q: Following results were recorded from a consolidation test on a specimen of saturated clay, each load…

A: After subjecting a saturated clay specimen to a consolidation test, each load was held constant for…

Q: A saturatéd specimen of cone! compression test apparatus and the sample failed at a deviator stress…

A:

Q: 8.2 The results of a laboratory consolidation test on a clay sample are given below. Pressure, o…

A: Given:- The results of a laboratory consolidation test on a clay sample are given below.

Q: With the aid of sketches, explain Terzaghi's Spring Analogy Model.

A: Answer:- Terzaghi spring analogy model:- Terzahi showed that the consolidation process in a clay…

Q: 5. A consolidated, undrained triaxial test is being carried out on a normally consolidated clay…

A: Given data- Unconsolidated triaxial test-

Q: A consolidated-undrained tri-axial test was conducted on a normally consolidated clay sample and the…

A:

Q: A) The results of two consolidated-drained triaxial tests on clay are given below in Table 2. Table…

A:

Q: The following data are given for the laboratory sample. go' = 175 kPa ; eo = 1.1 ; 0o + Ago' = 300…

A:

Q: 4. The construction of a 10m x 10m square water tank in a residential neighbourhood has been…

A: Tank size = 10 m × 10 mH = Thickness of clay layer = 6 m

Calculation of Settlement

The vertical displacement of the structural foundation due to the loading from the superstructure is known as settlement. It is due to the reduction of air voids present in the soil. The amount of vertical displacement depends on the bearing capacity of the soil on which the foundation is laid. The effect of the settlement depends on the magnitude of settlement, uniformity, and the structural design of the structure. The maximum allowable settlement for residential and office buildings should be less than 18 mm, for industrial buildings, it is 38 mm and for commercial buildings, it is 25 mm.