The time for 75% consolidation of a 25 mm clay specimen (drained at top and bottom) in the laboratory is 22 minutes. How long will it take for a 6 m thick clay layer (same clay) in the field to undergo 55% consolidation under the same pressure increment? In the field, there is a rock layer at the bottom of the clay layer.

Q: data are given from the laboratory consolidation test. e₁ = 1.10 σ= 65.0 kN/m² e₂ = σ₂=240.0 kN/m²…

A: The Compression Index (Cc) is equal to the slope of the graph of pressure versus void ratio (log…

Q: Experimental data for clay specimen obtained initial values of e1 = 1.12 and P1 = 90 kPa, and final…

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Q: Refer to the soil profile shown in figure below. A laboratory consolidati the results: o'c = 100 kPa…

A: Dry unit weight of sand γdsand=Gγw1+e=2.669.811+0.55=16.835kNm3Sat unit weight of sand…

Q: A 6 foot thick clay layer is determined to have the consolidation properties shown below. If the…

A: Consolidated settlement is the process by which the volume of soil is decreased by the removal of…

Q: A soil has a void ratio of 0.6 under a normal stress of 105 kPa. It is required to reduce the void…

A: Given: Normal stress 1 = 105 kPa Void ratio 1, e­1 = 0.6 Void ratio 2, e2 = 0.45 Compression index,…

Q: A sandstone sample was cleaned, dried, and saturated with water. The saturated sample was placed in…

A: The pore volume compressibility is given by: cf=-1Vp(dVpdP*)△P Where, Vp = Pore volume dVp = Change…

Q: A clay sample, originally 35 mm thick at a void ratio of 1.2 was subjected to a compressive load.…

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Q: Calculate the pore volume compressibility of a sandstone sample under confining pressure of 5000…

A: Given data: Confining pressure Psig Cumulative pore volume reduction cc 1000 0.122 2000 0.162…

Q: A saturated clay sample in an oedometer is under vertical pressure of 120 kPa and is at a normally…

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Q: The time required for a 50% consolidation of a 25mm thick layer drained both sides is  2 min 20…

A: Given: For 50% consolidation of a 25 mm thick layer having drainage both side , time required is…

Q: The initial and final void ratios of a clay sample in a consolidation test are 1 and 0.5,…

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Q: noedometer (consolidation) test is performed on a normally consolidated clay stratum that is 8 et…

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Q: A laboratory consolidation test on a 25 mm thick normally consolidated clay specimen showed the…

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Q: A dry sandstone sample of diameter 22 mm and length 35 mm weighs 32 g. the sample is crushed and a…

A: Pycnometer method is used for the determination of specific gravity of dry soil sample. It is a very…

Q: The time for 65% consolidation of a 19-mm clay specimen (drained at top and bottom) in the…

A: The coefficient of clay is : Cv=TvHdr2tFor the clay in laboratory and field the coeff. of…

Q: 3- The time for 65% consolidation of a 1.12-inch clay specimen (drained at top and bottom) in the…

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Q: The time required for a 50% consolidation of a 25 mm thick layer (drained at both and bottom) in the…

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Q: The time required for a 50% consolidation of a 25 mm thick layer (drained at both sides) in the…

A: solutionTime for 50% consolidationt=2min 20sec=140 secfrom settlement tableTv=0.197 for 50%…

Q: A decision has been made to consolidate the clay before the site development by applying an…

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Q: a. Explain the Mohr's circles shown in Figure Q2 for a series of undrained tests and consolidated…

A: Mohr circle : A graphical representation of a general condition of stress at a spot is Mohr's…

Q: The time required for 50% consolidation of a 20 mm- thick clay layer(drained at both top and bottom)…

A: It is required to determine the time of consolidation using the relation. Tv=CvtH2 Here Tv is the…

Q: Q1- In an Odometer test a specimen of saturated clay 26 mm thick reaches 58% consolidation in 31…

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Q: A site is underlain by a saturated clay layer with thickness = 5m. A sample extracted from the…

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Q: A fully saturated clay specimen is placed in a consolidometer and subjected to a loading of 200…

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Q: Scenario The concrete dam in the figure below is to be built on top of a soil whose profile consists…

A: Solving question 1Given data,question related to geotechnical engineering, FINDa) What will be the…

Q: A 3.75m clay layer in the field (drained on one side) is normally consolidated. When the pressure is…

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Q: A layer of normally consolidated, saturated silty clay of 1 m thickness is subjected to one…

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Q: a. What time will be required to attain the same degree of consolidation for a clay layer 3 m thick…

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Unit Conversion

Standard units are also called SI units. SI units are used for measuring a physical quantity satisfying certain conditions. There are two types of units: fundamental units and derived units. Fundamental units are physical quantities that are independent, that is, they do not depend on other quantities like mass, length, or time. There are plenty of quantities in our lives which need to be measured and compared. Measuring is the comparison of a particular physical quantity with its reference value. A unit is a measure of a fixed physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with.