uestion-2: In an Oedometer test on a 20 mm thick sample of saturated clay taken from a site, 50% consolidation was reached in 10 minutes. Solve for. i Time required for the clay layer of 5 m thickness at the site for 50% compression, if the there is drainage only towards the top. Assume that the laboratory sample and the clay layer ut the site are both subject to the sume increase in stress. ii. Time required for the clay layer to reach 90% consolidation. iii, Time required for the clay layer to reach 50% consolidation, if the layer has double drainage instead of single drainage?

Q: d) An oedometer test was also performed on a (saturated) reconstituted sample obtained at the site.…

A: Initial void ratio = 1.005 Initial sample height = 20 mm

Q: A series of CU triaxial compression tests have been performed with pore pressure mea- surements on…

A: Given that :-A few number of CU triaxial compression tests are performeddiameter = 2.50 in.…

Q: During an oedometer test on a specimen of saturated clay, the thickness of the specimen decreased…

A: Solution; Given that; Oedometer test; Change in thickness of specimen  ∆H=19.931-19.720∆H=0.211…

Q: Two drained triaxial tests were performed on a saturated overconsolidated clay and the results are…

A:

Q: A consolidated un-drained triaxial test was performed on a specimen of saturated clay with a kg…

A: Given : σ3 = 2.0 kg/cm2 σ1 - σ3 = 2.8 kg/cm2 u = 1.8 kg/cm2 θ = 57 o This is a problem of Soil where…

Q: A saturated clay sample in an oedometer is under vertical pressure of 120 kPa and is at a normally…

A:

Q: a sample was obtained from point a in the submerged clay layer shown below. It was determined that…

A: Find Saturated unit weight of…

Q: Cc = 0.2 and An oedometer test on a saturated clay soil gave the following results: Cs = 0.04. The…

A: Vertical effective stress, Increase in vertical stress, Water content, Thickness, To find:…

Q: - In a consolidated-drained triaxial test on a clay, the specimen failed at a deviator stress of…

A: We will use direct formula of principal stress relation.

Q: Problem 3) Shown below is a cross-section through a soil layer. A Shelby tube sample was taken from…

A: Ko = 0.5  Ā = -0.1 To find- Effective stress of the sample after extrusion Skempton (1954) and Ladd…

Q: A soft clay in an unconfined compression test did not develop a failure plane but bulged during the…

A:

Q: A dilatometer test (DMT) was conducted in a clay deposit. The water table was located at a depth of…

A:

Q: In a triaxial unconsolidated undrained (UU) test on a saturated clay sample, the cell pressure was…

A: given cell pressure=100 kPadeviator stress=150 kPa

Q: Friction angle of dry sand is 35°. In a direct shear test on this sand, a normal stress of 150kPa…

A: Given data : Normal stress (σn)=150 KPaFriction angle (ϕ)=35∘The given soil is sandy soil .Hence…

Q: A 2 m thick clay is singly drained. A structure founded on the surface applied an average stress…

A: Thickness of clay layer, Increase of average stress,

Q: SITUATION: The angle of friction of a compacted dry sand is 37°. In a direct shear test on the sand,…

A: We will apply formula of shear stress.

Calculation of Settlement

The vertical displacement of the structural foundation due to the loading from the superstructure is known as settlement. It is due to the reduction of air voids present in the soil. The amount of vertical displacement depends on the bearing capacity of the soil on which the foundation is laid. The effect of the settlement depends on the magnitude of settlement, uniformity, and the structural design of the structure. The maximum allowable settlement for residential and office buildings should be less than 18 mm, for industrial buildings, it is 38 mm and for commercial buildings, it is 25 mm.