The tin and zinc contents of a brass sample are analyzed with the following results yielded: a) Zn: 33.27, 33.37, and 33.34%; b) Sn: 0.022, 0.025 and 0.026% Which of the following is the correct mean value, the calculated standard deviation "s" and the coefficient of variation "cov" for Tin? (Answers in that sequence) mean-33.33%;s-0.052% and cov-0.16% mean-0.024%;s-0.032% and cov-5.3% mean-0.024%;s-0.0034% and cov-7,5% mean-0.024%s-0.0021% and cov-8.8% mean-0.024%;s 0.0021% and cov can not be calculated from the data set supplied

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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The tin and zinc contents of a brass sample are analyzed with the following results yielded:
a) Zn: 33.27, 33.37, and 33.34%; b) Sn: 0.022, 0.025 and 0.026%
Which of the following is the correct mean value, the calculated standard deviation "s" and the coefficient of variation "cov" for Tin? (Answers in that sequence)
mean-33.33%;s-0.052% and cov -0.16%
mean-0.024%;s-0.032%
and cov-5.3%
mean-0.024%;s-0.0034%
and cov - 7,5%
mean-0.024%s-0.0021%
mean-0.024%;s-0.0021%
and cov-8.8%
and cov can not be calculated from the data set supplied
Transcribed Image Text:The tin and zinc contents of a brass sample are analyzed with the following results yielded: a) Zn: 33.27, 33.37, and 33.34%; b) Sn: 0.022, 0.025 and 0.026% Which of the following is the correct mean value, the calculated standard deviation "s" and the coefficient of variation "cov" for Tin? (Answers in that sequence) mean-33.33%;s-0.052% and cov -0.16% mean-0.024%;s-0.032% and cov-5.3% mean-0.024%;s-0.0034% and cov - 7,5% mean-0.024%s-0.0021% mean-0.024%;s-0.0021% and cov-8.8% and cov can not be calculated from the data set supplied
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