Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $11,000? To decide, you select a random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ = $6439 and 2 $6101. At a=0.01, what should you conclude? Entry level architects Entry level architects In Denver, CO x₁ = 58,300 n₁ = 39 in Lincoln, NE x2 = 54,240 2 = 35 What are the null and alternative hypotheses for this test? OA. Ho: H1-H211,000 Ha 1-2=11,000 OD. Ho: H1 H211,000 Ha: 1-2 ≥11,000 Calculate the standardized test statistic. OB. Ho: H1 H2211,000 Ha 1-2 <11,000 OE. Ho: H1 H2 $11,000 Ha H1 H211,000 (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) What can you conclude about the data? OA. Reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $11,000. OB. Reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $11,000. OC. Fail to reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $11,000. OD. Fail to reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $11,000. 06. Ho HH2 11,000 Ha: H1-H2 $11,000 OF. Ho H1 H2 = 11,000 Ha: H1-H2*11,000 [C du cor
Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $11,000? To decide, you select a random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ = $6439 and 2 $6101. At a=0.01, what should you conclude? Entry level architects Entry level architects In Denver, CO x₁ = 58,300 n₁ = 39 in Lincoln, NE x2 = 54,240 2 = 35 What are the null and alternative hypotheses for this test? OA. Ho: H1-H211,000 Ha 1-2=11,000 OD. Ho: H1 H211,000 Ha: 1-2 ≥11,000 Calculate the standardized test statistic. OB. Ho: H1 H2211,000 Ha 1-2 <11,000 OE. Ho: H1 H2 $11,000 Ha H1 H211,000 (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) What can you conclude about the data? OA. Reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $11,000. OB. Reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $11,000. OC. Fail to reject Ho. At the 1% level of significance, there is sufficient evidence to reject the claim that the difference in mean annual salaries is $11,000. OD. Fail to reject Ho. At the 1% level of significance, there is insufficient evidence to reject the claim that the difference in mean annual salaries is $11,000. 06. Ho HH2 11,000 Ha: H1-H2 $11,000 OF. Ho H1 H2 = 11,000 Ha: H1-H2*11,000 [C du cor
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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