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The thickness (in millimeters) of the coating applied to hard drives is one characteristic that determines the usefulness of the product. When no unusual circumstances are present, the thickness (X) has a normal distribution with a mean of 5 mm and a standard deviation of 0.02 mm. Suppose that the process will be monitored by selecting a random sample of 16 drives from each shift's production and determining x, the mean coating thickness for the sample. USE SALT (a) Describe the sampling distribution of x for a random sample of size 16. The distribution of x is normal with mean 5 mm and standard deviation mm. (b) When no unusual circumstances are present, we expect x to be within 30 x of 5 mm, the desired value. An x value farther from 5 mm than 30 x is interpreted as an indication of a problem that needs attention. Calculate 5 ± 30x 5 - 30 x = 5 + 30 = mm mm (c) Referring to part (b), what is the probability that a sample mean will be outside 5 ± 30 - just by chance (that is, when there are no unusual circumstances)? (Round your answer to four decimal places.) (d) Suppose that a machine used to apply the coating is out of adjustment, resulting in a mean coating thickness of 5.02 mm. What is the probability that a problem will be detected when the next sample is taken? (Hint: This will occur if x > 5 + 30 × or x < 5 – 3σ × when µ = 5.02. Round your answer to four decimal places.)

The thickness (in millimeters) of the coating applied to hard drives is one characteristic that determines the usefulness of the product. When no unusual circumstances are present, the thickness (X) has a normal distribution with a mean of 5 mm and a standard deviation of 0.02 mm. Suppose that the process will be monitored by selecting a random sample of 16 drives from each shift's production and determining x, the mean coating thickness for the sample. USE SALT (a) Describe the sampling distribution of x for a random sample of size 16. The distribution of x is normal with mean 5 mm and standard deviation mm. (b) When no unusual circumstances are present, we expect x to be within 30 x of 5 mm, the desired value. An x value farther from 5 mm than 30 x is interpreted as an indication of a problem that needs attention. Calculate 5 ± 30x 5 - 30 x = 5 + 30 = mm mm (c) Referring to part (b), what is the probability that a sample mean will be outside 5 ± 30 - just by chance (that is, when there are no unusual circumstances)? (Round your answer to four decimal places.) (d) Suppose that a machine used to apply the coating is out of adjustment, resulting in a mean coating thickness of 5.02 mm. What is the probability that a problem will be detected when the next sample is taken? (Hint: This will occur if x > 5 + 30 × or x < 5 – 3σ × when µ = 5.02. Round your answer to four decimal places.)

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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The thickness (in millimeters) of the coating applied to hard drives is one characteristic that determines the usefulness of the product. When no unusual circumstances are present, the thickness (X) has a normal distribution with a mean of 5 mm and a standard deviation of 0.02 mm. Suppose that the process will be monitored by selecting a random sample of 16 drives from each shift's production and determining x, the mean coating thickness for the sample. USE SALT (a) Describe the sampling distribution of x for a random sample of size 16. The distribution of x is normal with mean 5 mm and standard deviation mm. (b) When no unusual circumstances are present, we expect x to be within 30 x of 5 mm, the desired value. An x value farther from 5 mm than 30 x is interpreted as an indication of a problem that needs attention. Calculate 5 ± 30x 5 - 30 x = 5 + 30 = mm mm (c) Referring to part (b), what is the probability that a sample mean will be outside 5 ± 30 - just by chance (that is, when there are no unusual circumstances)? (Round your answer to four decimal places.) (d) Suppose that a machine used to apply the coating is out of adjustment, resulting in a mean coating thickness of 5.02 mm. What is the probability that a problem will be detected when the next sample is taken? (Hint: This will occur if x > 5 + 30 × or x < 5 – 3σ × when µ = 5.02. Round your answer to four decimal places.)
Transcribed Image Text:The thickness (in millimeters) of the coating applied to hard drives is one characteristic that determines the usefulness of the product. When no unusual circumstances are present, the thickness (X) has a normal distribution with a mean of 5 mm and a standard deviation of 0.02 mm. Suppose that the process will be monitored by selecting a random sample of 16 drives from each shift's production and determining x, the mean coating thickness for the sample. USE SALT (a) Describe the sampling distribution of x for a random sample of size 16. The distribution of x is normal with mean 5 mm and standard deviation mm. (b) When no unusual circumstances are present, we expect x to be within 30 x of 5 mm, the desired value. An x value farther from 5 mm than 30 x is interpreted as an indication of a problem that needs attention. Calculate 5 ± 30x 5 - 30 x = 5 + 30 = mm mm (c) Referring to part (b), what is the probability that a sample mean will be outside 5 ± 30 - just by chance (that is, when there are no unusual circumstances)? (Round your answer to four decimal places.) (d) Suppose that a machine used to apply the coating is out of adjustment, resulting in a mean coating thickness of 5.02 mm. What is the probability that a problem will be detected when the next sample is taken? (Hint: This will occur if x > 5 + 30 × or x < 5 – 3σ × when µ = 5.02. Round your answer to four decimal places.)
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