Answered: The test statistic of z = 1.06 is… | bartleby

MATLAB: An Introduction with Applications

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The test statistic of \( z = 1.06 \) is obtained when testing the claim that \( p \neq 0.365 \).
a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.
b. Find the P-value.
c. Using a significance level of \( \alpha = 0.01 \), should we reject \( H_0 \) or should we fail to reject \( H_0 \)?

Click here to view page 1 of the standard normal distribution table.
Click here to view page 2 of the standard normal distribution table.

a. This is a ___________ two-tailed ___________ test.

b. P-value = __________ (Round to three decimal places as needed.)

**Standard Normal Distribution Table (Page 1)**

### Negative z Scores

The image displays a section of a standard normal distribution table for negative z-scores. The z-score table shows the cumulative area from the left under the standard normal curve.

#### Graph or Diagram Explanation

- The top right of the table includes a bell curve diagram, representing a normal distribution. The area to the left of the curve corresponds to the cumulative probability for negative z-scores, as shown in the table below.

#### Table Explanation

- **Rows and Columns:**
- Each row represents a different z-score value, incrementing by 0.1 (e.g., -3.4, -3.3, etc.).
- Columns represent the second decimal place of the z-score (e.g., .00, .01, .02, etc.).

- **Cumulative Probability:**
- Each cell in the table corresponds to the cumulative probability associated with that specific z-score combination.

- **Example Values:**
- For z = -3.4 and .00 column, the cumulative probability is .0003.
- For z = -3.0 and .05 column, the cumulative probability is .0013.

This table helps find probabilities and understand data distribution characteristics within a standard normal distribution, focusing on negative z-score values.

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reject Ho or should we fail to reject Ho? distribution table distribution table as needed.) support the clain ce to support the d ence to support the evidence to suppo 1 6 Y H N tv C FO & Standard Normal Distribution Table (Page 1) 7 9 MacBook Air U NEGATIVE z Scores J z -3.50 and lower -3.4 -3.3 -3.2 -3.1 -3.0 -2.9 -2.8 F7 e S74 M * Standard Normal (2) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 0001 8 0003 .0005 0007 0010 0013 .0019 0026 1 K DII FB 0003 .0005 .0007 .0009 .0013 0018 0025 V & a ( 6. 9 O 0003 0005 .0006 0009 0013 0018 0024 DD FO L ) O. V .0003 .0004 0006 .0009 0012 0017 0023 P F10 I command option .0003 .0004 .0006 .0008 .0012 0016 0023 - 0003 .0004 .0006 .0008 .0011 .0016 .0022 N fro { 4 [ ? 1 F11 +11 = 11 .06 0003 .0004 .0006 .0008 .0011 .0015 .0021 z F12 } 1 0 07 .0003 .0004 .0005 .0008 .0011 .0015 .0021 08 .0003 .0004 .0005 .0007 .0010 0014 0020 delete 38 return shi
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