The test statistic of z = 2.01 is obtained when testing the claim that p #0.462.a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.b. Find the P-value.c. Using a significance level of α = 0.10, should we reject Ho or should we fail to reject Ho?Click here to view page 1 of the standard normal distribution table.Click here to view page 2 of the standard normal distribution table.a. This is atest.b. P-value = (Round to three decimal places as needed.)c. Choose the correct conclusion below.A. Fail to reject Ho. There is sufficient evidence to support the claim that p # 0.462.B. Reject Ho. There is sufficient evidence to support the claim that p = 0.462.C. Reject Ho. There is not sufficient evidence to support the claim that p = 0.462.D. Fail to reject Ho. There is not sufficient evidence to support the claim that p # 0.462.Next

Given, The test statistic (z) = 2.01 significance level (α) = 0.10 The alternative hypothesis (Ha)…

Answered: The test statistic of z = 2.01 is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The test statistic of z = -2.13 is obtained when testing the claim that p<0.15. a. Using a significance level of a = 0.01, find the critical value(s). b. Should we reject Ho or should we fail to reject Ho? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. Standard normal distribution table (page 1) a. The critical value(s) is/are z = (Round to two decimal places as needed. Use a comma to separate answers as needed.) NEGATIV E z Scores Standard Normal (2) Distribution: Cumulative Area from the LEFT 01 .02 03 04 05 06 07 08 09 -3.50 and 0001 lower -3.4 0003 .0003 0003 0003 0003 0003 .0003 .0003 0003 .0002 -3.3 0005 0005 0004 0004 .0004 0004 0004 0004 .0003 -3.2 0007 0007 0006 0006 0006 0006 0006 .0005 .0005 .0005 -3.1 0010 0009 0009 0009 0008 0008 .0008 0008 .0007 .0007 -3.0 0013 0013 0013 0012 0012 .0011 0011 .0011 .0010 .0010 -2.9 0019 0018 0018 0017 0016 0016 0015 0015 .0014 0014 -2.8 0026 0025…
Please see below. I need help with this.
reject Ho or should we fail to reject Ho? distribution table distribution table as needed.) support the clain ce to support the d ence to support the evidence to suppo 1 6 Y H N tv C FO & Standard Normal Distribution Table (Page 1) 7 9 MacBook Air U NEGATIVE z Scores J z -3.50 and lower -3.4 -3.3 -3.2 -3.1 -3.0 -2.9 -2.8 F7 e S74 M * Standard Normal (2) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 0001 8 0003 .0005 0007 0010 0013 .0019 0026 1 K DII FB 0003 .0005 .0007 .0009 .0013 0018 0025 V & a ( 6. 9 O 0003 0005 .0006 0009 0013 0018 0024 DD FO L ) O. V .0003 .0004 0006 .0009 0012 0017 0023 P F10 I command option .0003 .0004 .0006 .0008 .0012 0016 0023 - 0003 .0004 .0006 .0008 .0011 .0016 .0022 N fro { 4 [ ? 1 F11 +11 = 11 .06 0003 .0004 .0006 .0008 .0011 .0015 .0021 z F12 } 1 0 07 .0003 .0004 .0005 .0008 .0011 .0015 .0021 08 .0003 .0004 .0005 .0007 .0010 0014 0020 delete 38 return shi

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