The table shows the laboratory results of the sieve analysis of a soilsample. Which of the following gives the classification of soil accordingto the Unified Soil Classification System.Sieve SizeDiameterPercent Passing, %44.75094102.00088200.85075400.42552600.250241000.150102000.075

Look at the % passing through sieve no 200=4%<50%⇒COARSE GRAINED SOIL

Answered: The table shows the laboratory results…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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With the aid of a diagram, explain how sieve analysis is conducted to determine the particle size distributions of soil
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The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 100 No. 8 2.380 100 No. 10 2.000 95 No. 20 0.840 81 No. 40 0.420 74 No. 60 0.250 69 No. 100 0.150 55 No. 200 0.075 51 Characteristics of No. 40 Fraction LL 48 PL 40 A. A-5(3) B. A-7-5(4) C. None of these. D. A-5(4) E. A-7-6(3)
200 pan 44 22
QUESTION 2 a. The results given in Table 1 were obtained in a particle size distribution test for soil sample received in the laboratory. Table 1 US Sieve No. Size Opening(mm) Weight Retained(g) 4 4.75 0 10 2.0 18.5 20 0.85 53.2 40 0.425 90.5 60 0.25 81.8 100 0.150 92.2 200 0.075 58.5 Pan - 26.5i. Determine the percentage passing each sieve and plot the particle size distribution curve. ii. How much fine-grained soils are in the sample ? iii. Determine the amount of gravel and sand in the sample ? iv. Determine D10, D30, and D60 from the grain-size distribution curve. v. Calculate the uniformity coefficient, Cu. vi. Calculate the coefficient of gradation, Cc. vii. Describe the gradation curve (eg poorly graded)
EXERCICE 4 Sieve analysis was performed from which the results were summarized in the following table. 1 a) Plot the grain size curve b) Calculate the coefficient of uniformity and the coefficient of gradation. c) Give a first idea about the classification of such soil. U.S. Sieve Opening (mm) Mass retained in each sieve (gr) 1 20 4 4.750 10 2.000 40 20 0.850 60 40 0.425 89 60 0.250 140 80 0.180 122 100 0.150 210 200 0.075 56 Pan 12
Following results are obtained from particle size analysis: Uniformity coefficient = 8 Coefficient of curvature = 2.8 Percentage of soil passing through 4.75 mm IS sieve = 70% If liquid limit and plastic limit for the soil are 38% and 34.2% respectively, the soil can be classified as per IS soil classification?
Problem 1 The resuts of a sieve analysis for a soil sample are given in the table. (a) Plot (to scale) the particle size distribution curve (b) Comment whether the soil is well graded, poorly graded or gap graded (c) Determine CU and CC (d) Determine percentages of gravel, sand and fines in the sample Sieve Opening (mm) Mass Retained (g) 4.75 20 2 51 1 126 0.85 24 0.25 115 0.075 68 Pan 27
The sieve analysis data for a granular soil are given below. % passing or finer 19 mm sieve = 100%% passing or finer 4.75 mm (4 sieve) = 61%% passing or finer 0.075mm (200 sieve) = 16% What are the percentages of gravels, sands and fines within this soil, based on the Unified Soil Classification System?
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Can I get a step by step for this question? Using the data presented for the given soil sample, determine the soil classification using the ASTM and the AASHTO Soil classification system. Give the group index if needed. The soil is inorganic soil. Sieve No. 19mm (¾ in.) 12.5mm (1/2in.) No. 4 (4.75 mm) No. 10 (2.00 mm) No. 20 (0.850 mm) No. 40 (0.425 mm) No. 100 (0.150 mm) No. 200 (0.075 mm) Percent Passing 100 95 63 50 44 37 28 22 Cu: 5.5 and Cc: 1.8 Atterberg limits: Liquid limit. 33%, Plasticity Index: 17%.
Subject: Geotechnical Engineering

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The table shows the laboratory results of the sieve analysis of a soil sample. Which of the following gives the classification of soil according to the Unified Soil Classification System.