Following results are obtained from particle size analysis: Uniformity coefficient = 8 Coefficient of curvature = 2.8 Percentage of soil passing through 4.75 mm IS sieve = 70% If liquid limit and plastic limit for the soil are 38% and 34.2% respectively, the soil can be classified as per IS soil classification?

Following results are obtained from particle size analysis: Uniformity coefficient = 8 Coefficient of curvature = 2.8 Percentage of soil passing through 4.75 mm IS sieve = 70% If liquid limit and plastic limit for the soil are 38% and 34.2% respectively, the soil can be classified as per IS soil classification?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The sieve analysis data for a granular soil are given below. % passing or finer 19 mm sieve = 100%% passing or finer 4.75 mm (4 sieve) = 61%% passing or finer 0.075mm (200 sieve) = 16% What are the percentages of gravels, sands and fines within this soil, based on the Unified Soil Classification System?
Engineering-- Civil Engineering--Geotechnical Engineering
The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 96 6 2.380 91 10 2.000 89 20 0.840 85 40 0.420 81 60 0.250 78 100 0.149 67 200 0.074 64 LL 40 PL 30 Determine its classification using USCS. ML MH None of the above CL CH
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