The systolic blood pressure of individuals is thought to be related to both age and weight. Let the systolic blood pressure, age, and weight be represented by the variables x1, x2, and x3, respectively. Suppose that Minitab was used to generate the following descriptive statistics, correlations, and regression analysis for a random sample of 15 individuals.  Descriptive Statistics Variable N Mean Median TrMean StDev SE Mean x 1 15 154.14 154.34 154.14 3.842 0.992000 x 2 15 59.69 60.19 59.69 1.462 0.377487 x 3 15 205.55 204.75 205.55 4.558 1.176871 ​ Variable Minimum Maximum Q1 Q3 x 1 125 178 141.803 167.244 x 2 41 80 47.754 78.415 x 3 126 240 140.395 224.008 ​ Correlations (Pearson)   x 1 x 2 x 2 0.892   x 3 0.839 0.567 Regression Analysis  The regression equation is  x 1 = 0.883 + 1.257x2 + 0.871x3  ​ Predictor Coef StDev T P Constant 0.883 0.635 1.39 0.095 x 2 1.257 0.635 1.98 0.036 x 3 0.871 0.419 2.08 0.030 S = 0.428 R-sq = 92.7 % R-sq(adj) = 92.8 %     ​ Find a 90% confidence interval for the coefficient of  in the regression equation. Round your final answers to three decimal places.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Author:Carter
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Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
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The systolic blood pressure of individuals is thought to be related to both age and weight. Let the systolic blood pressure, age, and weight be represented by the variables x1x2, and x3, respectively. Suppose that Minitab was used to generate the following descriptive statistics, correlations, and regression analysis for a random sample of 15 individuals.

 

Descriptive Statistics
Variable N Mean Median TrMean StDev SE Mean
x 1 15 154.14 154.34 154.14 3.842 0.992000
x 2 15 59.69 60.19 59.69 1.462 0.377487
x 3 15 205.55 204.75 205.55 4.558 1.176871

Variable Minimum Maximum Q1 Q3
x 1 125 178 141.803 167.244
x 2 41 80 47.754 78.415
x 3 126 240 140.395 224.008

Correlations (Pearson)
  x 1 x 2
x 2 0.892  
x 3 0.839 0.567

Regression Analysis

 

The regression equation is

 

x 1 = 0.883 + 1.257x2 + 0.871x

Predictor Coef StDev T P
Constant 0.883 0.635 1.39 0.095
x 2 1.257 0.635 1.98 0.036
x 3 0.871 0.419 2.08 0.030
S = 0.428 R-sq = 92.7 % R-sq(adj) = 92.8 %    

Find a 90% confidence interval for the coefficient of  in the regression equation. Round your final answers to three decimal places.

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