The standard Gibbs energy (p = 100 kPa, 25 °C) of formation of H2O (1) is 237.129 kJ mol-1 and its saturated vapor pressure at 25 °C is p = 3.17 kPa. Calculate the standard Gibbs energy of formation of H2O (g) at 25 °C. (Vm (H2O, 1) = 1.8 × 10-5 m³ mol-¹) Imol H2O(g) Imol H2O(l) 298.15K, p =100kPa AG AG (H₂O(1),298.15K) 298.15K, p = 100kPa AG (H₂O(g),298.15K) AG = AG(H₂O, 9, 298.15K) — 4G(H₂O,1,298.15K) Af Gm(H20, g, 298.15K) = ?

The standard Gibbs energy (p = 100 kPa, 25 °C) of formation of H2O (1) is 237.129 kJ mol-1 and its saturated vapor pressure at 25 °C is p = 3.17 kPa. Calculate the standard Gibbs energy of formation of H2O (g) at 25 °C. (Vm (H2O, 1) = 1.8 × 10-5 m³ mol-¹) Imol H2O(g) Imol H2O(l) 298.15K, p =100kPa AG AG (H₂O(1),298.15K) 298.15K, p = 100kPa AG (H₂O(g),298.15K) AG = AG(H₂O, 9, 298.15K) — 4G(H₂O,1,298.15K) Af Gm(H20, g, 298.15K) = ?

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter17: Chemcial Thermodynamics

Section: Chapter Questions

Problem 17.107QE: Calculate the standard Gibbs free-energy change when SO3 forms from SO2 and O2 at 298 K. Why is...

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