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- What is the organic product formed in the following reaction? C6H5-CH=CH-C-C6H5 ÷ (CH3CH2)2NH O C6H-CH-CH-C-C6H5 (CH3CH2)2N || III CH-CH, CH- (CH3CH2)2N -CH OH IV O-N(CH2CH3)2 C6H3-CH=CH-C-CH¸ CH-CH=CH-C-CHS (CH3CH₁₂N Select one: A. IV B. II OC. III D. I F1 10: - F2 80 F3 000 000 FA68. The primary reaction product of the reaction given be low is -CH-CH=CH2 + H,0What is/are the missing reagent(s) (A) in the following reaction? CH3-CH₂-C-OH O H₂SO4 O CH3OCH 3 O 1)CN 2) H3O+/heat O CrO3/H+ OCH3OH/H*/heat A CH3-CH₂-C-0-CH3
- (h) CHCO CI CH3CO2H, 50 °C Draw the major product(s) of the reaction.4. A student was asked to prepare an alkene X in high yield using any alcohol as starting material CH3 CH,-C -CH=CH, CH3 X He chose 3, 3-dimethylbutan-2-ol (XI) and carried out a dehydration reaction. He was however horrified to note that the only alkene obtained was XII. CH3 OH CH3 CH;-C=C-CH3 conc. H,SO4 CH-CH3 heat CH3 CH3 XI XII i) Explain what went wrong here, and why X could not be formed from 3, 3-dimethylbutan-2-ol. Use structures to help support your answer. ii) Give an equation to show a much better method for preparing X in high yield. 5. Analyze the following structure and write one combination for Grignard reagent and a carbonyl that would give rise to it. CH,-CH,-OHQ2. What are the products of the following reactions? ÇH3 (a) CH3CH2-C-CI + OCH,- CH, (b) CH;--O- + CH;-X CH3
- #2 - Draw the step-by-step mechanism for each of the steps in the following reaction sequence. Be sure to draw arrows for the movement of all electrons. Show any and all intermediates. ОН CH–C=C-CH2CH3 (1) Na* -:C=C-CH;CH3 NaNH, H-C=C-CH;CH3 (2) H;O+A(C3H₂O) 1)Mg 2)C6H5COMе HBr BrCH2–CH2–CHO OH Me C O O HOCH₂ CH₂OH H3O* B(CH₂O₂Br) Producto finalwhat should be the structures of F and G in the given reaction map in the photo?
- Which of the following is the product of the reaction below?Identify the missing major product or reagent in the numbers10:29 0. O ? 86% AIATS For Two Year Medic. A 61 /180 (02:55 hr min Mark for Review When 2-Methylpropene undergoes oxidation in the presence of acidic K2Cr2O7, the products obtained are CH3 – CH + CO2 CH3 — СH — С—ОН-СО, CH, -C =0+CO2 +H2O CH3 CH; – CH2 – CH + CO2 + H20 Clear Response III
