The reaction described by the equation   O3(g)+NO(g)⟶O2(g)+NO2(g)O3(g)+NO(g)⟶O2(g)+NO2(g)   has, at 310 K, the rate law   rate of reaction=?[O3][NO]?=3.0×106 M−1⋅s−1rate of reaction=k[O3][NO]k=3.0×106 M−1⋅s−1   Given that [O3]=3.0×10−4 M[O3]=3.0×10−4 M and [NO]=7.0×10−5 M[NO]=7.0×10−5 M at ?=0,t=0, calculate the rate of the reaction at ?=0. need to find: the rate  the overall order of the reaction

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The reaction described by the equation

 

O3(g)+NO(g)⟶O2(g)+NO2(g)O3(g)+NO(g)⟶O2(g)+NO2(g)

 

has, at 310 K, the rate law

 

rate of reaction=?[O3][NO]?=3.0×106 M−1⋅s−1rate of reaction=k[O3][NO]k=3.0×106 M−1⋅s−1

 

Given that [O3]=3.0×10−4 M[O3]=3.0×10−4 M and [NO]=7.0×10−5 M[NO]=7.0×10−5 M at ?=0,t=0, calculate the rate of the reaction at ?=0.

need to find:

the rate 

the overall order of the reaction

Expert Solution
Step 1

The reaction taking place is given as,

=> O3 (g) + NO (g) ------> O2 (g) + NO2 (g)

 

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