The reaction described by the equation 03 (g) + NO(g) has, at 310 K, the rate law O₂(g) + NO₂(g) rate of reaction = k[03][NO] k = 3.0 x 106 M-1.s-1 Given that [0₂] = 8.0 × 10-4 M and [NO] = 3.0 × 10-5 M at t = 0, calculate the rate of the reaction at t = 0.
The reaction described by the equation 03 (g) + NO(g) has, at 310 K, the rate law O₂(g) + NO₂(g) rate of reaction = k[03][NO] k = 3.0 x 106 M-1.s-1 Given that [0₂] = 8.0 × 10-4 M and [NO] = 3.0 × 10-5 M at t = 0, calculate the rate of the reaction at t = 0.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 31QRT
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![The reaction described by the equation
O₂(g) + NO(g) →→→ O₂(g) + NO₂(g)
has, at 310 K, the rate law
rate:
rate of reaction =
-4
Given that [03] = 8.0 × 10−4 M and [NO] = 3.0 × 10-5 M at t = 0, calculate the rate of the reaction at t = 0.
k[O3 ][NO] k = 3.0 × 106 M-¹.s-¹
What is the overall order of this reaction?
O 0
2
3
1
M/S](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F00154cd9-82c7-455b-845c-02cf21fdb65c%2F8b402e63-ce92-4d17-b540-2cf05f8c0bcb%2Fg15lrsd_processed.png&w=3840&q=75)
Transcribed Image Text:The reaction described by the equation
O₂(g) + NO(g) →→→ O₂(g) + NO₂(g)
has, at 310 K, the rate law
rate:
rate of reaction =
-4
Given that [03] = 8.0 × 10−4 M and [NO] = 3.0 × 10-5 M at t = 0, calculate the rate of the reaction at t = 0.
k[O3 ][NO] k = 3.0 × 106 M-¹.s-¹
What is the overall order of this reaction?
O 0
2
3
1
M/S
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