The reaction described by the equation 03 (g) + NO(g) has, at 310 K, the rate law O₂(g) + NO₂(g) rate of reaction = k[03][NO] k = 3.0 x 106 M-1.s-1 Given that [0₂] = 8.0 × 10-4 M and [NO] = 3.0 × 10-5 M at t = 0, calculate the rate of the reaction at t = 0.

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The reaction described by the equation
O₂(g) + NO(g) →→→ O₂(g) + NO₂(g)
has, at 310 K, the rate law
rate:
rate of reaction =
-4
Given that [03] = 8.0 × 10−4 M and [NO] = 3.0 × 10-5 M at t = 0, calculate the rate of the reaction at t = 0.
k[O3 ][NO] k = 3.0 × 106 M-¹.s-¹
What is the overall order of this reaction?
O 0
2
3
1
M/S
Transcribed Image Text:The reaction described by the equation O₂(g) + NO(g) →→→ O₂(g) + NO₂(g) has, at 310 K, the rate law rate: rate of reaction = -4 Given that [03] = 8.0 × 10−4 M and [NO] = 3.0 × 10-5 M at t = 0, calculate the rate of the reaction at t = 0. k[O3 ][NO] k = 3.0 × 106 M-¹.s-¹ What is the overall order of this reaction? O 0 2 3 1 M/S
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