The problem is: A cyclist won a bicycle race for seven consecutive years. His "winning" times and "victory" margins (time difference of the second-place finisher) are given in the figure below. Year Time (h:m:s) Margin (m:s) 1999 91:32:12 7:33 2000 92:33:05 6:02 2001 86:17:25 6:44 2002 82:05:17 7:16 2003 83:41:17 1:07 2004 83:36:02 6:11 2005 86:15:02 4:40how do I find the standard deviation of the cyclist's times? and of the cyclist's margins?

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The problem is: A cyclist won a bicycle race for seven consecutive years. His "winning" times and "victory" margins (time difference of the second-place finisher) are given in the figure below.

Year Time
(h:m:s)
Margin
(m:s)
1999 91:32:12 7:33
2000 92:33:05 6:02
2001 86:17:25 6:44
2002 82:05:17 7:16
2003 83:41:17 1:07
2004 83:36:02 6:11
2005 86:15:02 4:40
how do I find the standard deviation of the cyclist's times? and of the cyclist's margins? 
Expert Solution
Step 1

Based on the provided information, convert all the values in the table into seconds.

For Time, (Hours*3600)+(Minutes*60)+Seconds.

For margin, (Minutes*60)+Seconds

Year Time Margin
1999 329532 453
2000 333185 362
2001 310645 404
2002 295517 436
2003 301277 67
2004 300962 371
2005 310502 280
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