Suppose that the weight of an newborn fawn is Uniformly distributed between 1.6 and 3.2 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. c. The probability that fawn will d. The probability that a newborn fawn will be weigh between 1.7 a. The mean of this distribution is b. The standard deviation is weigh exactly 2.7 kg is P(x = 2.7) =

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Suppose that the weight of an newborn fawn is Uniformly distributed between 1.6 and 3.2 kg. Suppose that a
newborn fawn is randomly selected. Round answers to 4 decimal places when possible.
a. The mean of this distribution is
b. The standard deviation is
c. The probability that fawn will
weigh exactly 2.7 kg is P(x = 2.7) =
d. The probability that a newborn fawn will be weigh between 1.7
and 2.2 is P(1.7 <x<2.2) =
e. The probability that a newborn fawn will be weigh more than 2.02 is P(x
> 2.02) =
f. P(x > 2.2 | x< 2.8) =
g. Find the 48th percentile.
Transcribed Image Text:Suppose that the weight of an newborn fawn is Uniformly distributed between 1.6 and 3.2 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. a. The mean of this distribution is b. The standard deviation is c. The probability that fawn will weigh exactly 2.7 kg is P(x = 2.7) = d. The probability that a newborn fawn will be weigh between 1.7 and 2.2 is P(1.7 <x<2.2) = e. The probability that a newborn fawn will be weigh more than 2.02 is P(x > 2.02) = f. P(x > 2.2 | x< 2.8) = g. Find the 48th percentile.
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