The photoelectron spectrum for water has four bands, not including ionizations from the 1s electrons of oxygen. Three of the bands have vibrational fine structure. The fourth band, which is from the least energetic ionization, shows no such fine structure. Explain these results in terms of your MO scheme.
The photoelectron spectrum for water has four bands, not including ionizations from the 1s electrons of oxygen. Three of the bands have vibrational fine structure. The fourth band, which is from the least energetic ionization, shows no such fine structure. Explain these results in terms of your MO scheme.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1) The photoelectron spectrum for water has four bands, not including ionizations from the 1s electrons of oxygen. Three of the bands have vibrational fine structure. The fourth band, which is from the least energetic ionization, shows no such fine structure. Explain these results in terms of your MO scheme.
2) If we added two more electron pairs to the MO scheme for BeH2, this would describe the bonding in water if water were a linear molecule. Compare your MO scheme for bent water with this hypothetical scheme for linear water, and comment on why water is bent instead of linear.
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