Find the hybrid orbital type for each atom, the carbon-carbon-oxygen bond angle, the molecular geometry of oxygen, and the number of sigma and pi bonds in the molecule.
A. If l.p. + sigma bonds around an atom are 4, 3 and 2 respectively then hybridization of that atom will be sp3, sp2 and sp respectively.
Also, if no. of π bonds around an atom are 0, 1 and 2 respectively then hybridization of that atom will be sp3, sp2 and sp respectively.
On the basis of this the left N atom is sp2 hybridized while the right N atom is sp hybridized. The C atom attached to right N is sp hybridized. The another C atom attached to O atom is sp2 hybridized. The O atom is sp3 hybridized.
B. The C-C-C bond angle for sp3, sp2 and sp hybridization respectively involves bond angle of 109.5°, 120° and 180° respectively.
As C-C-N middle C is sp2 hybridized, the C-C-N atom has 120° bond angle as it is sp2 hybridized.
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