The bond angles in antimony trifluoride are 87°. Describe the bonding in SbF3, including a picture of the orbital overlap interaction that creates the Sb-F bonds. ✓orbitals from the inner atom. An outer halogen atom always uses one of orbitals to form a bond. Antimony has n = vvalence orbitals, and fluorine has n = vvalence orbitals, orbital from Sb and a Bond angles near 90° signal interactions of valence its valence so each of the three bonds in SbF3 can be described as resulting from overlap between a orbital from F. There are three bonds that point at near-right angles to one another.
The bond angles in antimony trifluoride are 87°. Describe the bonding in SbF3, including a picture of the orbital overlap interaction that creates the Sb-F bonds. ✓orbitals from the inner atom. An outer halogen atom always uses one of orbitals to form a bond. Antimony has n = vvalence orbitals, and fluorine has n = vvalence orbitals, orbital from Sb and a Bond angles near 90° signal interactions of valence its valence so each of the three bonds in SbF3 can be described as resulting from overlap between a orbital from F. There are three bonds that point at near-right angles to one another.
Chemistry: The Molecular Science
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Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter6: Covalent Bonding
Section: Chapter Questions
Problem 36QRT: Light of appropriate wavelength can break chemical bonds. Light having λ < 240 nm can dissociate...
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![The bond angles in antimony trifluoride are 87°. Describe the bonding in SbF3, including a picture of the orbital overlap interaction that
creates the Sb-F bonds.
✓orbitals from the inner atom. An outer halogen atom always uses one of
✓valence orbitals, and fluorine has n = vvalence orbitals,
Bond angles near 90° signal interactions of valence
its valence
✓orbitals to form a bond. Antimony has n =
so each of the three bonds in SbF3 can be described as resulting from overlap between a
orbital from F. There are three
vorbital from Sb and a
bonds that point at near-right angles to one another.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa4dccb3a-1afc-4ab2-9907-28cf59a229bd%2F16f6a639-aea1-4e4e-bced-33b782e17885%2Fhujaeg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The bond angles in antimony trifluoride are 87°. Describe the bonding in SbF3, including a picture of the orbital overlap interaction that
creates the Sb-F bonds.
✓orbitals from the inner atom. An outer halogen atom always uses one of
✓valence orbitals, and fluorine has n = vvalence orbitals,
Bond angles near 90° signal interactions of valence
its valence
✓orbitals to form a bond. Antimony has n =
so each of the three bonds in SbF3 can be described as resulting from overlap between a
orbital from F. There are three
vorbital from Sb and a
bonds that point at near-right angles to one another.
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