Complete the MO diagram (below) to determine if BN is paramagnetic or diamagnetic. Here's a detailed description of what appears in the image for educational purposes:---**Question 17 of 20****Task:** Complete the Molecular Orbital (MO) diagram to determine if BN (Boron Nitride) is paramagnetic or diamagnetic.**Diagram Explanation:**The MO diagram illustrated presents several molecular orbitals labeled with their types:1. **σ_s** (sigma-s) - The lowest energy level, typically represents the bonding between s orbitals.2. **σ_s*** (sigma-s star) - An antibonding orbital for the s orbitals.3. **π_p** and **π_p** - Degenerate pi bonding orbitals from p orbitals.4. **σ_p** (sigma-p) - A non-degenerate sigma bonding orbital for p orbitals.5. **π_p*** and **π_p*** - Degenerate pi antibonding orbitals from p orbitals.6. **σ_p*** (sigma-p star) - Highest energy level, an antibonding orbital for the p orbitals.**Objective:** Determine whether BN is paramagnetic or diamagnetic based on the electron configuration within this MO diagram.**Options:**A) ParamagneticB) Diamagnetic---To answer the question, the student would fill the orbitals with the appropriate number of electrons based on BN's electronic configuration and then determine whether any unpaired electrons remain. If there are unpaired electrons, BN is paramagnetic. If all electrons are paired, BN is diamagnetic.

Molecular orbitals are formed by the Linear Combination of Atomic Orbitals (LCAO). Number of molecular orbitals formed is always equal to the number of atomic orbitals combined. There are three types of molecular orbitals that is Bonding molecular orbital, Non-bonding molecular orbital and Anti-bonding molecular orbital.Molecular orbital diagram of BN is given below: As the Highest occupied Molecular orbital has unpaired electrons. So, the given molecule is paramagnetic. So, the correct option is (a) paramagnetic.