In reference to the following figure, which of the following statements is true?
a. An energy level diagram can be made of the two overlapping 1s orbitals, and the Aufbau process used to determine the electronic configurations of H2 and He2.
b. In-phase overlap of electron waves represented by the two 1s orbitals results in a new orbital having lower energy than either of the s orbitals. This new bonding orbital concentrates the electron probability between the two nuclei.
c. Out-of-phase overlap between two 1s orbitals results in a new orbital having higher energy than either of the s orbitals. This new antibonding orbital would place most of the electron probability to the left and right of the two nuclei.
d. The energy-lowering of the bonding molecular orbital and energy-raising of the antibonding molecular orbital with respect to the atomic orbitals will result in equal energy splitting with no net bonding between helium atoms.
e. All of the above statements are true.


A molecular orbital can be made by combining the atomic orbitals of the atoms and aufbau process can be used to determine the electronic configuration of molecules.
In phase overlap between the atomic orbitals result in the generation of lower energy molecular orbital than either of the atomic orbital. This new bonding molecular orbital concentrates the electron density between the two atoms
Out of phase overlap between the atomic orbitals result in the generation of higher energy molecular orbital than either of the atomic orbital. This new antibonding molecular orbitals result in no between between the nuclei and the electron density is concentrated at the left and right end of the two nuclei.
The same number of electrons in lower energy bonding molecular orbital and higher energy anti bonding molecular orbital cancel out the bonding interaction between the two atoms and there is no bond formation between the two atoms.
Bond order = number of bonds between the atoms
Bond order = (nb - na)
nb = number of electrons in bonding orbitals
na = number of electrons in anti bonding orbitals
If bond order = 0, no bond formation.
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