The pH for 0.0850 M solution of C,H,CH,COOH is 2.68. Determine the value of Ka for C H̟CH,COOH. 1 2 NEXT Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. C,H̟CH,COOH(a. q) HO(1) H,O(aq) CH,CH,COO(aq Initial (M) Change (M) Equilibrium (M)
The pH for 0.0850 M solution of C,H,CH,COOH is 2.68. Determine the value of Ka for C H̟CH,COOH. 1 2 NEXT Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. C,H̟CH,COOH(a. q) HO(1) H,O(aq) CH,CH,COO(aq Initial (M) Change (M) Equilibrium (M)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The problem presented is to determine the value of Ka for C₆H₅CH₂COOH, given that the pH of a 0.0850 M solution of C₆H₅CH₂COOH is 2.68.
The task is to fill in the ICE (Initial, Change, Equilibrium) table to determine the concentrations of all reactants and products for the dissociation reaction of C₆H₅CH₂COOH in water.
### Header:
A progress indicator shows step 1 of 2, with a "Next" button.
### Instructions:
"Based on the given values, fill in the ICE table to determine concentrations of all reactants and products."
### ICE Table for Reaction:
\[ \text{C}_6\text{H}_5\text{CH}_2\text{COOH (aq)} + \text{H}_2\text{O (l)} \rightleftharpoons \text{H}_3\text{O}^+ (\text{aq}) + \text{C}_6\text{H}_5\text{CH}_2\text{COO}^- (\text{aq}) \]
### ICE Table Columns:
- **Initial (M):**
C₆H₅CH₂COOH (aq) | H₃O⁺ (aq) | C₆H₅CH₂COO⁻ (aq)
Blank spaces provided for input.
- **Change (M):**
C₆H₅CH₂COOH (aq) | H₃O⁺ (aq) | C₆H₅CH₂COO⁻ (aq)
Blank spaces provided for input.
- **Equilibrium (M):**
C₆H₅CH₂COOH (aq) | H₃O⁺ (aq) | C₆H₅CH₂COO⁻ (aq)
Blank spaces provided for input.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4741ac40-39e9-49a8-a2ed-11d4120a8d1f%2Fee939500-e29e-4a1f-a800-4ebdd55dfe08%2F0w6pto_processed.png&w=3840&q=75)
Transcribed Image Text:The problem presented is to determine the value of Ka for C₆H₅CH₂COOH, given that the pH of a 0.0850 M solution of C₆H₅CH₂COOH is 2.68.
The task is to fill in the ICE (Initial, Change, Equilibrium) table to determine the concentrations of all reactants and products for the dissociation reaction of C₆H₅CH₂COOH in water.
### Header:
A progress indicator shows step 1 of 2, with a "Next" button.
### Instructions:
"Based on the given values, fill in the ICE table to determine concentrations of all reactants and products."
### ICE Table for Reaction:
\[ \text{C}_6\text{H}_5\text{CH}_2\text{COOH (aq)} + \text{H}_2\text{O (l)} \rightleftharpoons \text{H}_3\text{O}^+ (\text{aq}) + \text{C}_6\text{H}_5\text{CH}_2\text{COO}^- (\text{aq}) \]
### ICE Table Columns:
- **Initial (M):**
C₆H₅CH₂COOH (aq) | H₃O⁺ (aq) | C₆H₅CH₂COO⁻ (aq)
Blank spaces provided for input.
- **Change (M):**
C₆H₅CH₂COOH (aq) | H₃O⁺ (aq) | C₆H₅CH₂COO⁻ (aq)
Blank spaces provided for input.
- **Equilibrium (M):**
C₆H₅CH₂COOH (aq) | H₃O⁺ (aq) | C₆H₅CH₂COO⁻ (aq)
Blank spaces provided for input.
![**Question:**
The pH for a 0.0850 M solution of C\(_6\)H\(_5\)CH\(_2\)COOH is 2.68. Determine the value of K\(_a\) for C\(_6\)H\(_5\)CH\(_2\)COOH.
---
**Instructions:**
Based on your ICE table and definition of K\(_a\), set up the expression for K\(_a\) and then evaluate it. Do not combine or simplify terms.
---
\[ K_a = \dfrac{[\text{H}^+][\text{C}_6\text{H}_5\text{CH}_2\text{COO}^-]}{[\text{C}_6\text{H}_5\text{CH}_2\text{COOH}]} = \]
\[ \boxed{} \]
(Note: The box is meant for students to fill in with calculated values.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4741ac40-39e9-49a8-a2ed-11d4120a8d1f%2Fee939500-e29e-4a1f-a800-4ebdd55dfe08%2Fqsa452r_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
The pH for a 0.0850 M solution of C\(_6\)H\(_5\)CH\(_2\)COOH is 2.68. Determine the value of K\(_a\) for C\(_6\)H\(_5\)CH\(_2\)COOH.
---
**Instructions:**
Based on your ICE table and definition of K\(_a\), set up the expression for K\(_a\) and then evaluate it. Do not combine or simplify terms.
---
\[ K_a = \dfrac{[\text{H}^+][\text{C}_6\text{H}_5\text{CH}_2\text{COO}^-]}{[\text{C}_6\text{H}_5\text{CH}_2\text{COOH}]} = \]
\[ \boxed{} \]
(Note: The box is meant for students to fill in with calculated values.)
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